如何从匹配模式的向量中删除所有元素？

Question

ncvars = c("prate", "arate", "wpd", "Atm1", "Atm2", "area", "fC", "bas__1", "bas__asssaa", "bas__Clow", "bas__g2333e", "baser__arge", "bas__Aow", "bas__Aass")

现在，我想删除所有

正是名字 area
匹配这个字符串 bas__

我该怎么做？

试用

patterns <- c("bas__", "area")
ncvars %>%
  filter(.,grepl(paste(patterns, collapse="|")))

Answer 1

你可以用 ! 否定 grepl 并且要精确匹配，你需要 ^..$ 锚来匹配开始（^）和结束（$) 的字符串：

ncvars[!grepl('^area$|bas__', ncvars)]

ncvars
# [1] "prate"       "arate"       "wpd"         "Atm1"        "Atm2"        "area"        "fC"          "bas__1"     
# [9] "bas__asssaa" "bas__Clow"   "bas__g2333e" "baser__arge" "bas__Aow"    "bas__Aass"  
ncvars[!grepl('^area$|bas__', ncvars)]
# [1] "prate"       "arate"       "wpd"         "Atm1"        "Atm2"        "fC"          "baser__arge"

Answer 2

一个tidyverse解决方案：

library(stringr)
stringr::str_subset(ncvars, pattern = "^area$|^bas__", negate = TRUE)
[1] "prate"       "arate"       "wpd"         "Atm1"        "Atm2"        "fC"          "baser__arge"

如何从匹配模式的向量中删除所有元素？

How can I remove all elements from a vector that matches a pattern?

r

subset

grepl