Netlogo：如何获取Netlogo中的累计值？

Question

我已经在the link上确认了信息。但是我无法应用它。以下是示例模型程序的一部分。我想累加海龟的数量，但是我不能用示例程序累加它。我可能需要你的建议。谢谢。

globals [num-turtles cumulative-sum average-time number-dead ]
turtles-own [count-up]

to setup
  clear-all
  set num-turtles 5
  reset-ticks
end

to go

  if count turtles < num-turtles
  [ ask patch 0 0
    [ sprout 1
      [ set count-up 0 ]
    ]
  ]

  set cumulative-sum cumulative-sum + 1 ;I would like to calculate the integral value here, but this syntax is not a cumulative value. 
  ask (turtles-on patch 0 0)
    [
      set cumulative-sum count turtles-here
    ]

  set average-time ifelse-value (number-dead = 0)
  [ 0 ][(cumulative-sum) / (number-dead)]

  if (count turtles > 0) [
    ask min-one-of turtles [who] [
      if count-up >= 6 [
        set number-dead number-dead + 1
        die
      ]
    ]
  ]

  ask (turtles-on patch 0 0)
  [ set count-up count-up + 1
  ]

  tick
end

Answer 1

好多了，谢谢-我现在可以运行代码没问题了。但是，我认为我仍然不理解您想要 cumulative-sum 实际计数的内容。您是否只是在寻找海龟总数，包括还活着的和已经死亡的海龟？如果是这样，我认为这只是移动 set cumulative-sum cumulative-sum + 1 行的问题。例如：

编辑：

好的，我想我现在从你的评论中明白了。试试这个：

globals [num-turtles cumulative-sum average-time number-dead ]
turtles-own [count-up]

to setup
  clear-all
  set num-turtles 5
  reset-ticks
end

to go

  if count turtles < num-turtles [
    ask patch 0 0 [
      sprout 1 [
        set count-up 0
      ]
    ]
  ] 

  if (count turtles > 0) [
    ask min-one-of turtles [who] [
      if count-up >= 6 [
        set number-dead number-dead + 1
        die
      ]
    ]
  ]

  ask turtles-on patch 0 0 [
    set count-up count-up + 1
  ]

  set cumulative-sum cumulative-sum + count turtles
  set average-time ifelse-value (number-dead = 0) [0]  [(cumulative-sum) / (number-dead)]

  tick
end

Netlogo：如何获取Netlogo中的累计值？

Netlogo: How can I obtain the accumulate value in Netlogo?

integrated

netlogo

cumulative-sum