Python 将元组列表中的值求和到特定值
Python sum values in list of tuples up to certain values
注意:我编辑了问题!
我在 Python 中遇到迭代问题,尤其是当我想将值加起来达到某个数字时。以下是有关我面临的问题的更多信息:
我有一个元组列表,如下所示:
[(1, 0.5, 'min'),
(2, 3, 'NA'),
(3, 6, 'NA'),
(4, 40, 'NA'),
(5, 90, 'NA'),
(6, 130.8, 'max'),
(7, 129, 'NA'),
(8, 111, 'NA'),
(9, 8, 'NA'),
(10, 9, 'NA'),
(11, 0.01, 'min'),
(12, 9, 'NA'),
(13, 40, 'NA'),
(14, 90, 'NA'),
(15, 130.1, 'max'),
(16, 112, 'NA'),
(17, 108, 'NA'),
(18, 90, 'NA'),
(19, 77, 'NA'),
(20, 68, 'NA'),
(21, 0.9, 'min'),
(22, 8, 'NA'),
(23, 40, 'NA'),
(24, 90, 'NA'),
(25, 92, 'NA'),
(26, 130.4, 'max')]
我想将导致 "max" 的每个值和导致 "min" 的每个值相加,并将这些结果附加到两个单独的列表中。
例如,输出应该是:
min_sums = [1+2+3+4+5,11+12+13+14, 21+22+23+24+15]
max_sums = [6+7+8+9+10, 15+16+17+18+19+20, 26]
我还想跟踪我实际总结的值,并将其作为输出:
min_sums_lst = [[1,2,3,4,5], [11,12,13,14],[21,22,23,24,15]]
max_sums_lst = [[6,7,8,9,10], [15,16,17,18,19,20], [26]]
我想我可以使用索引值,但我对 Python 还很陌生,不确定如何继续。我正在学习生物学,但我相信学习 CS 可以帮助我的工作。
max_list = []
min_list = []
flag = ''
min_index = 0
max_index = float('inf');
if flag == 'h':
max_list.append(item)
elif flag == 'c':
min_list.append(item)
for i, item in enumerate(minmax_list):
print(i, item)
print("max_index: ", max_index)
print("min_index: ", min_index)
if item[2] == 'min':
min_index = i
max_list('h', item[0])
elif item[2] == 'NA' and (i < max_index):
max_list('h', item[0])
elif item[2] == 'max':
max_index = i
max_list('c', item[0])
elif item[2] == 'NA' and (i > min_index):
min_list('c', item[0])
我是 Python 的新手 - 任何帮助将不胜感激。我只是尝试根据上面输出中所示的最小值和最大值在每个元组中添加第一项。
抱歉,没有仔细阅读您的尝试,看起来很复杂。
min_sums = []
max_sums = []
for x, _, what in minmax_list:
if what != 'NA':
current = min_sums if what == 'min' else max_sums
current.append(0)
current[-1] += x
我的回答与@Stefan 的回答略有不同。它做了更多的验证,除了 'min' 和 'max'.
之外,您可以很容易地添加其他类型
def partition_items(items):
lists = {
'min': [],
'max': [],
}
current_kind = None
current_list = None
for value, _, kind in items:
if kind != current_kind and kind != 'NA':
current_kind = kind
# You'll get a error here if current_kind isn't one of 'min'
# or 'max'.
current_list = lists[current_kind]
current_list.append(0)
# You'll get an error here if the first item in the list doesn't
# have type of 'min' or 'max'.
current_list[-1] += value
return lists
lists = partition_items(items)
print(lists['min'])
# -> [15, 50, 115]
print(lists['max'])
# -> [40, 105, 26]
注意:我编辑了问题!
我在 Python 中遇到迭代问题,尤其是当我想将值加起来达到某个数字时。以下是有关我面临的问题的更多信息:
我有一个元组列表,如下所示:
[(1, 0.5, 'min'),
(2, 3, 'NA'),
(3, 6, 'NA'),
(4, 40, 'NA'),
(5, 90, 'NA'),
(6, 130.8, 'max'),
(7, 129, 'NA'),
(8, 111, 'NA'),
(9, 8, 'NA'),
(10, 9, 'NA'),
(11, 0.01, 'min'),
(12, 9, 'NA'),
(13, 40, 'NA'),
(14, 90, 'NA'),
(15, 130.1, 'max'),
(16, 112, 'NA'),
(17, 108, 'NA'),
(18, 90, 'NA'),
(19, 77, 'NA'),
(20, 68, 'NA'),
(21, 0.9, 'min'),
(22, 8, 'NA'),
(23, 40, 'NA'),
(24, 90, 'NA'),
(25, 92, 'NA'),
(26, 130.4, 'max')]
我想将导致 "max" 的每个值和导致 "min" 的每个值相加,并将这些结果附加到两个单独的列表中。
例如,输出应该是:
min_sums = [1+2+3+4+5,11+12+13+14, 21+22+23+24+15]
max_sums = [6+7+8+9+10, 15+16+17+18+19+20, 26]
我还想跟踪我实际总结的值,并将其作为输出:
min_sums_lst = [[1,2,3,4,5], [11,12,13,14],[21,22,23,24,15]]
max_sums_lst = [[6,7,8,9,10], [15,16,17,18,19,20], [26]]
我想我可以使用索引值,但我对 Python 还很陌生,不确定如何继续。我正在学习生物学,但我相信学习 CS 可以帮助我的工作。
max_list = []
min_list = []
flag = ''
min_index = 0
max_index = float('inf');
if flag == 'h':
max_list.append(item)
elif flag == 'c':
min_list.append(item)
for i, item in enumerate(minmax_list):
print(i, item)
print("max_index: ", max_index)
print("min_index: ", min_index)
if item[2] == 'min':
min_index = i
max_list('h', item[0])
elif item[2] == 'NA' and (i < max_index):
max_list('h', item[0])
elif item[2] == 'max':
max_index = i
max_list('c', item[0])
elif item[2] == 'NA' and (i > min_index):
min_list('c', item[0])
我是 Python 的新手 - 任何帮助将不胜感激。我只是尝试根据上面输出中所示的最小值和最大值在每个元组中添加第一项。
抱歉,没有仔细阅读您的尝试,看起来很复杂。
min_sums = []
max_sums = []
for x, _, what in minmax_list:
if what != 'NA':
current = min_sums if what == 'min' else max_sums
current.append(0)
current[-1] += x
我的回答与@Stefan 的回答略有不同。它做了更多的验证,除了 'min' 和 'max'.
之外,您可以很容易地添加其他类型def partition_items(items):
lists = {
'min': [],
'max': [],
}
current_kind = None
current_list = None
for value, _, kind in items:
if kind != current_kind and kind != 'NA':
current_kind = kind
# You'll get a error here if current_kind isn't one of 'min'
# or 'max'.
current_list = lists[current_kind]
current_list.append(0)
# You'll get an error here if the first item in the list doesn't
# have type of 'min' or 'max'.
current_list[-1] += value
return lists
lists = partition_items(items)
print(lists['min'])
# -> [15, 50, 115]
print(lists['max'])
# -> [40, 105, 26]