jq：从嵌套对象中选择键的子集

Question

输入：

{"success": true, "results": {"a": …, "b": …, "c": …}}

期望的输出，因为我想保留 b:

{"success": true, "results": {"b": …}}

我尝试过的事情：

$ jq 'del(select(.results.b | not))'
{"success": true, "results": {"a": …, "b": …, "c": …}}
# removes nothing from "results"

$ jq 'with_entries(select(.key == "success" or .key == "results.b"))'
{"success": true}
# nested comparison not understood; returns only "success"

谢谢！

Answer 1

另一种使用nodejs and shell的方式：

代码：

$ node<<EOF
var obj = $(</tmp/file.json);
delete obj.results.a;
delete obj.results.c;
console.log(JSON.stringify(obj));
EOF

输出：

{"success":true,"results":{"b":"bbb"}}

Answer 2

这是一种解决方案：

.results |= {b}

样本运行

$ jq -M '.results |= {b}' <<< '{"success":true, "results":{"a": "…", "b": "…", "c": "…"}}'
{
  "success": true,
  "results": {
    "b": "…"
  }
}

Try it online at jqplay.org

jq：从嵌套对象中选择键的子集

jq: selecting subset of keys from nested object

json

nested

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jq

代码：

输出：