如何以编程方式检查 'Face Id' 和 'Touch Id' 的支持

Question

出于我的应用程序安全目的，我已经集成了 LocalAuthentication，它一直支持基于 'Touch Id' 的支持。但是现在，苹果最近也添加了基于 'Face Id' 的身份验证。

我如何检查设备支持哪种类型的身份验证。 Touch ID 还是 Face ID？

Answer 1

同Xcode9，看LocalAuthentication -> LAContext -> LABiometryType.

LABiometryType 是一个枚举，其值如附图

您可以查看设备在 Touch ID 和 FaceID 或 none 之间支持的身份验证类型。

编辑：

Apple 已更新此枚举的值 LABiometryType。 none 现已弃用。

用于检查支持的生物识别类型的扩展 Swift 5:

import LocalAuthentication

extension LAContext {
    enum BiometricType: String {
        case none
        case touchID
        case faceID
    }

    var biometricType: BiometricType {
        var error: NSError?

        guard self.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: &error) else {
            return .none
        }

        if #available(iOS 11.0, *) {
            switch self.biometryType {
            case .none:
                return .none
            case .touchID:
                return .touchID
            case .faceID:
                return .faceID
            @unknown default:
                #warning("Handle new Biometric type") 
            }
        }
        
        return  self.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: nil) ? .touchID : .none
    }
}

Answer 2

我一直在努力让它工作，发现我需要使用 LAContext 的单个实例并且需要调用 LAContextInstance.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: nil) 在获取 biometryType 之前。这是我支持旧 iOS 版本的最终代码：

import LocalAuthentication

static func biometricType() -> BiometricType {
    let authContext = LAContext()
    if #available(iOS 11, *) {
        let _ = authContext.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: nil)
        switch(authContext.biometryType) {
        case .none:
            return .none
        case .touchID:
            return .touch
        case .faceID:
            return .face
        }
    } else {
        return authContext.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: nil) ? .touch : .none
    }
}

enum BiometricType {
    case none
    case touch
    case face
}

Answer 3

这是通过属性的另一种方法（例如，在您的访问实例上）。

import LocalAuthentication


enum BiometricType {
    case none
    case touchID
    case faceID
}

var biometricType: BiometricType {
    get {
        let context = LAContext()
        var error: NSError?

        guard context.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: &error) else {
            print(error?.localizedDescription ?? "")
            return .none
        }

        if #available(iOS 11.0, *) {
            switch context.biometryType {
            case .none:
                return .none
            case .typeTouchID:
                return .touchID
            case .typeFaceID:
                return .faceID
            }
        } else {
            return  .touchID
        }
    }
}

Answer 4

Objective C :)

/** Only interesting devices are enumerated here. To change view constraints depending
 on screen height. Or the top notch for iPhone X
 */
typedef NS_ENUM(NSUInteger, BPDeviceType) {
    BPDeviceTypeUnknown,
    BPDeviceTypeiPhone4,
    BPDeviceTypeiPhone5,
    BPDeviceTypeiPhone6,
    BPDeviceTypeiPhone6Plus,
    BPDeviceTypeiPhone7,
    BPDeviceTypeiPhone7Plus,
    BPDeviceTypeiPhoneX,
    BPDeviceTypeiPad
};

+ (BPDeviceType)getDeviceType {
    double screenHeight = [[UIScreen mainScreen] bounds].size.height;
    if(UI_USER_INTERFACE_IDIOM()==UIUserInterfaceIdiomPad)
    {
        return BPDeviceTypeiPad;

    } else if (UI_USER_INTERFACE_IDIOM()== UIUserInterfaceIdiomPhone)
    {
        if (@available(iOS 11, *)) {
            UIEdgeInsets insets = [UIApplication sharedApplication].delegate.window.safeAreaInsets;
            if (insets.top > 0) {
                return BPDeviceTypeiPhoneX;
            }
        }

        if(screenHeight == 480) {
            return BPDeviceTypeiPhone4;
        } else if (screenHeight == 568) {
            return BPDeviceTypeiPhone5;
        } else if (screenHeight == 667) {
            return BPDeviceTypeiPhone6;
        } else if (screenHeight == 736) {
            return BPDeviceTypeiPhone6Plus;
        }
    }
    return BPDeviceTypeUnknown;
}

+ (BOOL) isBiometricIDAvailable {
    if (![LAContext class]) return NO;

    LAContext *myContext = [[LAContext alloc] init];
    NSError *authError = nil;
    if (![myContext canEvaluatePolicy:LAPolicyDeviceOwnerAuthenticationWithBiometrics error:&authError]) {
        NSLog(@"%@", [authError localizedDescription]);
        return NO;
    }
    return YES;
}

+ (BOOL) isTouchIDAvailable {
    if (![LAContext class]) return NO;

    LAContext *myContext = [[LAContext alloc] init];
    NSError *authError = nil;
    if (![myContext canEvaluatePolicy:LAPolicyDeviceOwnerAuthenticationWithBiometrics error:&authError]) {
        NSLog(@"%@", [authError localizedDescription]);
        return NO;
        // if (authError.code == LAErrorTouchIDNotAvailable) {}
    }

    if (@available(iOS 11.0, *)) {
        if (myContext.biometryType == LABiometryTypeTouchID){
            return YES;
        } else {
            return NO;
        }
    } else {
        return YES;
    }
}

+ (BOOL) supportFaceID {
    return [BPDeviceInfo getDeviceType] == BPDeviceTypeiPhoneX;
}

+ (BOOL) isFaceIDAvailable {
    if (![LAContext class]) return NO;

    LAContext *myContext = [[LAContext alloc] init];
    NSError *authError = nil;
    if (![myContext canEvaluatePolicy:LAPolicyDeviceOwnerAuthenticationWithBiometrics error:&authError]) {
        NSLog(@"%@", [authError localizedDescription]);
        return NO;
    }

    if (@available(iOS 11.0, *)) {
        if (myContext.biometryType == LABiometryTypeFaceID){
            return YES;
        } else {
            return NO;
        }
    } else {
        return NO;
    }
}

Answer 5

此代码在 Xcode 9.2-9.4 上构建时没有警告（请参阅 9.1 的注释）：

@objc let biometricsAuthPolicy = LAPolicy.deviceOwnerAuthenticationWithBiometrics

@objc func supportsFaceID() -> Bool {
    if #available(iOS 11.0, *) {
        return biometryType() == .faceID // return biometryType() == .typeFaceID for Xcode 9.1
    }
    return false
}

@objc func supportsTouchID() -> Bool {
    if #available(iOS 11.0, *) {
        return biometryType() == .touchID // return biometryType() == .typeTouchID for Xcode 9.1
    }

    let context = LAContext()
    return context.canEvaluatePolicy(biometricsAuthPolicy, error: nil)
}

@objc @available(iOS 11.0, *)
func biometryType() -> LABiometryType {
    var error: NSError?
    let context = LAContext()

    guard context.canEvaluatePolicy(biometricsAuthPolicy, error: &error) else {
        if #available(iOS 11.2, *) {
            return .none
        }
        return LABiometryType.LABiometryNone // return LABiometryType.none for Xcode 9.1
    }

    return context.biometryType
}

Answer 6

面容 ID 可从 iOS 11 开始使用，iPhone X 默认带有 iOS 11。在 LocalAuth 框架中，他们添加了一个 'biometryType' 属性，它可以让你检测设备上是否有 Face ID。

/// checks if face id is avaiable on device
func faceIDAvailable() -> Bool {
    if #available(iOS 11.0, *) {
        let context = LAContext()
        return (context.canEvaluatePolicy(LAPolicy.deviceOwnerAuthentication, error: nil) && context.biometryType == .faceID)
    }
    return false
}

Answer 7

因为我是扩展的忠实粉丝。我对这个答案的措辞略有不同。本质是一样的。这是一个插入式扩展。

import LocalAuthentication

extension LAContext {
    enum BiometricType: String {
        case none
        case touchID
        case faceID
    }

    var biometricType: BiometricType {
        var error: NSError?

        guard self.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: &error) else {
            // Capture these recoverable error thru Crashlytics
            return .none
        }

        if #available(iOS 11.0, *) {
            switch self.biometryType {
            case .none:
                return .none
            case .touchID:
                return .touchID
            case .faceID:
                return .faceID
            }
        } else {
            return  self.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: nil) ? .touchID : .none
        }
    }
}

这样使用：

var currentType = LAContext().biometricType

Answer 8

这是我的"helper class"，它还包括密码

enum BiometryType: String {
    case none = "None"
    case faceID = "Face ID"
    case touchID = "Touch ID"
    case passcode = "Passcode"
}


var biometryType: BiometryType {
    let myContext = LAContext()

    let hasAuthenticationBiometrics = myContext.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: nil)
    let hasAuthentication = myContext.canEvaluatePolicy(.deviceOwnerAuthentication, error: nil)

    if #available(iOS 11.0, *) {
        if hasAuthentication {
            if hasAuthenticationBiometrics {
                switch myContext.biometryType {
                case .none: return .none
                case .faceID: return .faceID
                case .touchID: return .touchID
                }
            } else {
                return .passcode
            }
        } else {
            return .none
        }
    } else {
        if hasAuthentication {
            if hasAuthenticationBiometrics {
                return .touchID
            } else {
                return .passcode
            }
        } else {
            return .none
        }
    }
}

Answer 9

来自@Markicevic 扩展，但忽略用户未注册等情况...

extension LAContext {

enum BiometricType: String {
    case none = ""
    case touchID = "Touch ID"
    case faceID = "Face ID"
}

static var biometricType: BiometricType {
    var error: NSError?

    let context = LAContext()

    _ = context.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: &error)

    if error?.code == LAError.Code.touchIDNotAvailable.rawValue {
        return .none
    }

    if #available(iOS 11.0, *) {
        switch context.biometryType {
        case .none:
            return .none
        case .touchID:
            return .touchID
        case .faceID:
            return .faceID
        }
    } else {
        return  context.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: nil) ? .touchID : .none
    }
}

}

Answer 10

我为本地身份验证制作了一个单例 class，因为它有助于为整个应用程序使用 static 属性一次性初始化一个实例。

import Foundation
import LocalAuthentication

public class LocalAuthManager: NSObject {

    public static let shared = LocalAuthManager()
    private let context = LAContext()
    private let reason = "Your Request Message"
    private var error: NSError?

    enum BiometricType: String {
        case none
        case touchID
        case faceID
    }

    private override init() {

    }

    // check type of local authentication device currently support
    var biometricType: BiometricType {
        guard self.context.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: &error) else {
            return .none
        }

        if #available(iOS 11.0, *) {
            switch context.biometryType {
            case .none:
                return .none
            case .touchID:
                return .touchID
            case .faceID:
                return .faceID
            }
        } else {
            return self.context.canEvaluatePolicy(.deviceOwnerAuthentication, error: nil) ? .touchID : .none
        }
    }
}

实施：

func checkAuth() {
     let authType = LocalAuthManager.shared.biometricType
        switch authType {
        case .none:
            print("Device not registered with TouchID/FaceID")
        case .touchID:
            print("Device support TouchID")
        case .faceID:
            print("Device support FaceID")
        }
 }

Answer 11

-(BOOL)faceIDAvailable {
        LAContext *myContext = [[LAContext alloc] init];
        NSError *authError = nil;

        if (@available(iOS 11.0, *)) {
            if ([myContext canEvaluatePolicy:LAPolicyDeviceOwnerAuthentication error:&authError] && myContext.biometryType == LABiometryTypeFaceID) {
                return true;
            }
        }
      return false;

}
-(BOOL)touchIDAvailable {
        LAContext *myContext = [[LAContext alloc] init];
        NSError *authError = nil;

        if (@available(iOS 11.0, *)) {
            if ([myContext canEvaluatePolicy:LAPolicyDeviceOwnerAuthentication error:&authError] && myContext.biometryType == LABiometryTypeTouchID) {
                return true;
            }
        }
      return false;

}

Answer 12

更新swift5，切换流程需要一个默认条件。

import Foundation
import LocalAuthentication

extension LAContext {
    enum BiometricType: String {
        case none
        case touchID
        case faceID
    }

    var biometricType: BiometricType {
        var error: NSError?

        guard self.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: &error) else {
            // Capture these recoverable error through fabric
            return .none
        }

        if #available(iOS 11.0, *) {
            switch self.biometryType {
            case .touchID:
                return .touchID
            case .faceID:
                return .faceID
            default:
                return .none
            }
        }

        return self.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: nil) ? .touchID : .none
    }

}

测试用例在下面

// need to import LocalAuthentication in the calling file
// import LocalAuthentication
let currentType = LAContext().biometricType
print("biometry type > \(currentType)")
// biometry type > touchID

如果你想在模拟器中测试，你需要注册touchId/faceId。
Simulator > Hardware > Touch ID/Face ID > Enrolled。

Answer 13

请参考苹果为"Logging a User into Your App with Face ID or Touch ID"提供的示例代码，这将有助于轻松理解身份验证。

Apple 示例代码 link - https://docs-assets.developer.apple.com/published/fbfd13f4d9/LoggingAUserIntoYourAppWithFaceIDOrTouchID.zip

阅读下方示例代码的详细解释link。 https://developer.apple.com/documentation/localauthentication/logging_a_user_into_your_app_with_face_id_or_touch_id

Answer 14

开始在 12 Pro 上测试一些新应用，发现我发布的应用只有 Touch ID 而没有 Face ID。

我来到这里看到了所有这些，所以我开始尝试更改我的 Touch ID 代码，但我需要做的就是将隐私密钥添加到 info.plist。

资讯属性列表➕

然后向下滚动到：隐私 - Face ID 使用说明，（类型：字符串），（值：是）

太容易了

Answer 15

您需要在案例中添加@unknown！！！

在较新的版本中（Xcode 13...）您可能必须指定“未知”

#warning("Handle new Biometric type") 没有 return 值

import LocalAuthentication

class BiometricType{


static func biometricType() -> BiometricType {
    let authContext = LAContext()
    if #available(iOS 11, *) {
        let _ = authContext.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: nil)
        switch(authContext.biometryType) {
        case .none:
            return .none
        case .touchID:
            return .touch
        case .faceID:
            return .face
        @unknown default:
            return .unknown
        }
    } else {
        return authContext.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: nil) ? .touch : .none
    }
}

enum BiometricType {
    case none
    case touch
    case face
    case unknown
}

}

如何以编程方式检查 'Face Id' 和 'Touch Id' 的支持

How to programmatically check support of 'Face Id' and 'Touch Id'

ios

touch-id

ios11

localauthentication

face-id

您需要在案例中添加@unknown！！！