使用带有 WIREMOCK 的 XML 模板发送 soap 请求（在 java 中）

Question

我刚开始使用 WIREMOCK 并尝试在 Java 中发送带有 XML template 的请求。我看到了一些 JSON 的例子，但我找不到任何 Java 的例子。（我的意思是使用 XML file 创建请求模板并将其发送到 Web 服务。）

Answer 1

您可以在简单的 HttpURLConnection 中将内容作为内容主体发送

示例代码：

URL endpoint = null;

endpoint = new URL("https://someurlhere.com");

conn = (HttpURLConnection) endpoint.openConnection();

// Set the necessary header fields

//The SOAPAction is required to be blank
/*The presence and content of the SOAPAction header field can be used by servers such as firewalls to appropriately
filter SOAP request messages in HTTP. The header field value of empty string ("") means that the intent of the SOAP
message is provided by the HTTP Request-URI. No value means that there is no indication of the intent of the message.*/
conn.addRequestProperty("SOAPAction", "");
//Telling the server not to Skip the SOAPAction. It's a mandatory field when we send SOAP Requests.
conn.addRequestProperty("Skip SOAP Action", "false");
conn.addRequestProperty("Content-Type", "text/xml;charset=UTF-8");

//We use POST because we are sending data to the server
conn.setRequestMethod("POST");
//This is required to read response from Server
conn.setDoOutput(true);
//The server has 5 seconds to respond. Else, a timeout occurs and the connection is terminated.
conn.setConnectTimeout(5000);

// Send the request
OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream());
wr.write(xmlContent);
wr.flush();


// Read the response
BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream()));
String temp;

//Reading as long as there is response to read
while ((temp = rd.readLine()) != null) {
    response += temp;
}

如您所见，我们正在向服务器发送一个名为 xmlContent 的字符串。使用您选择的 xml 文件设置内容，它会起作用。

使用带有 WIREMOCK 的 XML 模板发送 soap 请求（在 java 中）

sending soap request with an XML template with WIREMOCK (in java)

java

soap

request

wiremock