为什么在设置脚本执行顺序时仍然先执行一个脚本？

Question

我有两个脚本附加到同一个空游戏对象。第一个脚本是：

using System;
using System.Collections;
using System.Collections.Generic;
using System.IO;
using UnityEngine;

public class SpawnObjects : MonoBehaviour
{
    public int numberOfObjects;
    public GameObject objectToPlace;
    public Vector3 newObjectsSize = new Vector3(5, 5, 5);
    public float spawnSpeed = 0.1f;

    private int wallsLengthX;
    private int wallsLengthZ;
    private int wallsPosX;
    private int wallsPosZ;
    private int currentObjects;
    private List<GameObject> objects = new List<GameObject>();

    void Start()
    {
        var wi = GetComponent<Walls>();
        wallsLengthX = (int)wi.lengthX;
        wallsLengthZ = (int)wi.lengthZ;
        wallsPosX = (int)wi.wallsStartPosition.x;
        wallsPosZ = (int)wi.wallsStartPosition.z;

        StartCoroutine(Spawn());
    }

    IEnumerator Spawn()
    { 
        for (int i = 0; i < numberOfObjects; i++)
        {
            GameObject newObject = (GameObject)Instantiate(objectToPlace);
            newObject.transform.localScale = new Vector3(newObjectsSize.x, newObjectsSize.y, newObjectsSize.z);
            newObject.transform.localPosition = GenerateRandomPositions(newObject);
            newObject.name = "Spawned Object";
            newObject.tag = "Spawned Object";
            objects.Add(newObject);
            yield return new WaitForSeconds(spawnSpeed);
            currentObjects += 1;
        }
    }

    private Vector3 GenerateRandomPositions(GameObject newObject)
    {
        float paddingX = Mathf.Clamp(newObject.transform.localScale.x, 0, wallsLengthX) / 2f;
        float paddingZ = Mathf.Clamp(newObject.transform.localScale.z, 0, wallsLengthZ) / 2f;
        float originX = wallsPosX + paddingX - wallsLengthX / 2f;
        float originZ = wallsPosZ + paddingZ - wallsLengthZ / 2f;
        float posx = UnityEngine.Random.Range(originX, originX + wallsLengthX - paddingX);
        float posz = UnityEngine.Random.Range(originZ, originZ + wallsLengthZ - paddingZ);
        float posy = Terrain.activeTerrain.SampleHeight(new Vector3(posx, 0, posz));

        return new Vector3(posx, posy, posz);
    }
}

第二个脚本：

using System.Collections;
using System.Collections.Generic;
using UnityEngine;

public class WayPoints : MonoBehaviour
{
    public GameObject[] waypoints;
    public Transform target;
    public float moveSpeed = 10f;
    public float moveSpeed1 = 10f;
    public float slowDownSpeed = 3f;
    public float reverseSlowDownSpeed = 3f;
    public float rotationSpeed = 1f;

    private Transform myTransform;
    private int targetsIndex = 0;
    private Vector3 originalPosition;
    private GameObject[] robots;

    public Transform reverseTarget;
    private int reverseTargetsIndex = 0;
    private Vector3 reverseOriginalPosition;

    public bool random = false;

    void Awake()
    {
        myTransform = transform;
    }
    // Use this for initialization
    void Start()
    {
        waypoints = GameObject.FindGameObjectsWithTag("Spawned Object");

第一个脚本产生了 10 个新的立方体。但是第二个脚本 waypoints 变量只得到 1 "Spawned Object" 而不是 10.

当我使用断点时，我看到它正在执行循环中的第一个脚本：

for (int i = 0; i < numberOfObjects; i++)

但随后它跳转到第二个脚本得到一个 "Spawned Object" 然后回到第一个脚本并完成循环的其余部分。

我想要的是，它首先使整个循环产生 10 个立方体，然后用第二个脚本获得它们。

我什至在编辑器中做了：编辑 > 项目设置 > 脚本执行顺序但它仍然没有首先执行整个循环，只迭代一次。

Answer 1

你在 Spawn() 协程中有收益：

yield return new WaitForSeconds(spawnSpeed);

Start() 函数正在以正确的顺序调用，但第一个脚本只是启动一个协程，该协程在每次迭代后产生。在第一次 yield 之后，它会等到 WaitForSeconds 结束后再继续；与此同时，第二个脚本将运行它的 Start().

作为解决方案，您无法通过脚本执行顺序来解决此问题。您的第二个脚本必须等到第一个脚本完成运行其 Spawn() 协程。有很多方法可以做到这一点，但最简单的方法是公开 StartCoroutine() 返回的 Coroutine 对象，或者在 SpawnObjects class.

为什么在设置脚本执行顺序时仍然先执行一个脚本？

Why when setting the order of scripts executing still one script is executing first?

c#

unity3d

unity5