订单日 sql select

Question

美好的一天！我有一个 table 填充日期时间数据类型，它存储为 nvarchar。我需要 select 从 table 得到按天排序的结果日期插入此形状。

>Thursday 11:30-12:30
>Sunday 08:00-09:00
>Sunday 08:00-09:00
>Sunday 08:00-09:00
>Sunday 08:00-09:00
>Monday 08:00-09:00
>Monday 09:00-10:00
>Monday 08:00-09:00

我试过用这个

SELECT TOP 1000 [Class_Time_ID] ,[Class_ID] ,[Class_Date]
FROM [School].[dbo].[Class_Time_Table] 
ORDER BY CASE Class_Date WHEN 'Monday' THEN 2 
                         WHEN 'Tuesday' THEN 3 
                         WHEN 'Wednesday' THEN 4 
                         WHEN 'Thursday' THEN 5 
                         WHEN 'Sunday' THEN 1
         end

Answer 1

一个Class_Date（例如'Monday 09:00-10:00'）永远不会等于 'Monday'，但它就像'Monday%':

SELECT
  class_time_id,
  class_id,
  class_date
FROM school.dbo.class_time_table
ORDER BY CASE
  WHEN class_date LIKE 'Monday%' THEN 2 
  WHEN class_date LIKE 'Tuesday%' THEN 3 
  WHEN class_date LIKE 'Wednesday%' THEN 4 
  WHEN class_date LIKE 'Thursday%' THEN 5 
  WHEN class_date LIKE 'Sunday%' THEN 1 
END

Answer 2

使用 CROSS APPLY 可能会有所帮助，因为它允许在 select 和 where 子句中使用 case expression 的别名。例如

SQL Fiddle

MS SQL Server 2014 架构设置:

CREATE TABLE Class_Time_Table
    ([Class_Date] varchar(20), [Class_Time_ID] int ,[Class_ID] int)
;

INSERT INTO Class_Time_Table
    ([Class_Date])
VALUES
    ('Thursday 11:30-12:30'),
    ('Sunday 08:00-09:00'),
    ('Sunday 08:00-09:00'),
    ('Sunday 08:00-09:00'),
    ('Sunday 08:00-09:00'),
    ('Monday 08:00-09:00'),
    ('Monday 09:00-10:00'),
    ('Monday 08:00-09:00')
;

查询 1:

SELECT
       ctt.*
      , ca.day_of_week,ca.start_time,ca.end_time
FROM Class_Time_Table ctt
CROSS APPLY (
      SELECT
            CASE
                  WHEN class_date LIKE 'Monday%' THEN 2
                  WHEN class_date LIKE 'Tuesday%' THEN 3
                  WHEN class_date LIKE 'Wednesday%' THEN 4
                  WHEN class_date LIKE 'Thursday%' THEN 5
                  WHEN class_date LIKE 'Sunday%' THEN 1
            END                                    AS day_of_week
          , SUBSTRING(RIGHT(class_date, 11), 1, 5) AS start_time
          , SUBSTRING(RIGHT(class_date, 5) , 1, 5)  AS end_time
  ) ca 
order by day_of_week, start_time, end_time

Results:

|           Class_Date | Class_Time_ID | Class_ID | day_of_week | start_time | end_time |
|----------------------|---------------|----------|-------------|------------|----------|
|   Sunday 08:00-09:00 |        (null) |   (null) |           1 |      08:00 |    09:00 |
|   Sunday 08:00-09:00 |        (null) |   (null) |           1 |      08:00 |    09:00 |
|   Sunday 08:00-09:00 |        (null) |   (null) |           1 |      08:00 |    09:00 |
|   Sunday 08:00-09:00 |        (null) |   (null) |           1 |      08:00 |    09:00 |
|   Monday 08:00-09:00 |        (null) |   (null) |           2 |      08:00 |    09:00 |
|   Monday 08:00-09:00 |        (null) |   (null) |           2 |      08:00 |    09:00 |
|   Monday 09:00-10:00 |        (null) |   (null) |           2 |      09:00 |    10:00 |
| Thursday 11:30-12:30 |        (null) |   (null) |           5 |      11:30 |    12:30 |

订单日 sql select

order day sql select

sql

sql-server

select

nvarchar