尝试为 if 语句设置两个条件

Question

每当我运行这段代码时，它总是转到 else 语句。如果满足符号兼容的条件，则输出将始终不兼容。我究竟做错了什么？ sign 和 sign2 是十二生肖的变量。我正在使用十二生肖元素来查看两个星座是否相互兼容。

def zodiacCompatibility(sign, sign2):
fire = ["Aries, Leo, Sagittarius"]
earth = ["Capricorn, Taurus, Virgo"]
water = ["Pisces, Cancer, Scorpio"]
air = ["Gemini, Aquarius, Libra"]


if (sign in fire and sign2 in fire):
    result = ("The two signs are compatible")
if (sign in earth and sign2 in earth):
    result = ("The two signs are compatible")
if (sign in air and sign2 in air):
    result = ("The two signs are compatible")
if (sign in water and sign2 in water):
    result = ("The two signs are compatible")
if (sign in fire and sign2 in air):
    result = ("The two signs are compatible")
if (sign in water and sign2 in earth):
    result = ("The two signs are compatible")
if (sign in air and sign2 in fire):
    result = ("The two signs are compatible")
if (sign in earth and sign2 in water):
    result = ("The two signs are compatible")
else:
    result = ("The two signs are not compatible")

finalResult = zodiacCompatibility(sign, sign2)

打印（最终结果）

Answer 1

我想你想做的是：

if (condition):
elif (condition):
elif (condition):
.
.
.
else:

您的代码当前所做的是遍历每个 if 语句。如果满足其中一个或多个条件，它将写入 result，然后再次重写。它进入 else statement 的原因是因为它的符号不在地球上并且符号 2 不在水中。

我想你想要的是，如果满足 none 个条件，它就会转到 else 语句。这可以实现到我上面输入的结构。

[这里有更多信息]1 关于 if 语句及其对应物如何工作的信息。

尝试为 if 语句设置两个条件

Trying to have two conditions for an if statement

python-3.6