tkinter 动态 OptionMenu 命令不起作用

Question

我正在使用 python 2.7.9，我当前的问题是由于某种原因，我的 OptionMenu 命令无法正常工作。下面是我的意思的示例代码。

from Tkinter import *

root = Tk()
var = StringVar()
var.set("Choose a name...")
names = []

# Appends names to names list and updates OptionMenu
def createName(n):
    names.append(n)
    personName.delete(0, "end")
    menu = nameMenu['menu']
    menu.delete(0, "end")
    for name in names:
        menu.add_command(label=name, command=lambda name=name: var.set(name))

# what to run when a name is selected
def selection():
    print "Running"  # For testing purposes to see when/if selection runs
    print var.get()

# Option Menu for names
nameMenu = OptionMenu(root, var, (), command=lambda: selection())
nameMenu.grid(row=0, column=0, columnspan=2)
nameMenu.config(width=20)

# Entry for user to submit name
Label(root, text="Name").grid(row=1, column=0)
personName = Entry(root, width=17)
personName.grid(row=1, column=1)

# Add person Button
Button(root, text="Add Person", width=20, command=
       lambda: createName(personName.get())).grid(row=5, column=0, columnspan=2)

mainloop()

这个理论程序的目的只是在OptionMenu中添加一个名字，然后当你select这个名字时，它会打印出来。我可以将名称添加到 OptionMenu 就好了，但是当 OptionMenu 到运行和 selection() 函数时，它不会。

现在我对错误的最佳猜测只是按钮调用的 createName() 函数也使用了 OptionMenu 的命令，因为行

menu.add_command(label=name, command=lambda name=name: var.set(name))

这附近有没有？ OptionMenu 是否可以有多个命令？

Answer 1

您走在正确的轨道上...但是您可以像这样将名称传递给 selection() 函数，而不是更改 StringVar：

from Tkinter import *

root = Tk()

var = StringVar()
var.set("Choose a name...")
names = []

# Appends names to names list and updates OptionMenu
def createName(n):
    names.append(n)
    personName.delete(0, "end")
    menu = nameMenu['menu']
    menu.delete(0, "end")
    for name in names:
        menu.add_command(label=name, command=lambda name=name: selection(name))

# what to run when a name is selected
def selection(name):
    var.set(name)
    print "Running"  # For testing purposes to see when/if selection runs
    print name

# Option Menu for names
nameMenu = OptionMenu(root, var, ())
nameMenu.grid(row=0, column=0, columnspan=2)
nameMenu.config(width=20)

# Entry for user to submit name
Label(root, text="Name").grid(row=1, column=0)
personName = Entry(root, width=17)
personName.grid(row=1, column=1)


# Add person Button
Button(root, text="Add Person", width= 20, command=lambda: createName(personName.get())).grid(row=5, column=0, columnspan=2)


mainloop()

tkinter 动态 OptionMenu 命令不起作用

tkinter dynamic OptionMenu command not working

python

tkinter

optionmenu