发送电子邮件时收件人在密件抄送字段中

Question

每当我运行我的代码时，收件人都在密件抄送字段中而不是 To 字段中（当我检查我的 gmail 收件箱时）

我不知道是什么原因。我怎样才能阻止收件人进入密件抄送字段。并使它们出现在 TO 字段中这是我的代码

import smtplib 
import getpass
import time
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText

smtpVar = smtplib.SMTP ("smtp.gmail.com", 587)
fromEmail = "myemail@gmail.com"
toEmails = ["myemail@gmail.com", "secondemail@gmail.com"]

msgVar = MIMEMultipart()
msgVar ["From"] = fromEmail
msgVar ["To"] = toEmails

# I am getting the contents of the body of the email from a text file
fileOpen1 = open ("EmailBody.txt", "r")
msgBody = MIMEText (fileOpen1.read())
fileOpen1.close()

smtpVar.ehlo()
smtpVar.starttls()

passwordVar = getpass.getpass (prompt="Enter Password  : ")
smtpVar.login ("myemail@gmail.com", passwordVar)

smtpVar.sendmail (msgVar ["From"], msgVar ["To"] , "Subject: Test Email-.......[Email Date/Time] " + time.strftime("%Y" + "-" + "%m" + "-" + "%d" + "_" + "%H" + ":" + "%M" + ":" + "%S") + "\n" + msgBody.as_string())

smtpVar.quit()
print ("\n\n.....message sent successfully!!!\n\n")

Answer 1

smtplib 不会为您创建消息 header。 from 和 to 参数仅用于信封。如果您想让它们出现在 header 中，您必须自己动手。

smtpVar.sendmail (msgVar ["From"], msgVar ["To"] , "From: " + msgVar["From"] + "\nTo: " + msgVar["To"].join(", ") + "\nSubject: Test Email-.......[Email Date/Time] " + time.strftime("%Y-%m-%d_%H:%M:%S") + "\n" + msgBody.as_string())

发送电子邮件时收件人在密件抄送字段中

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smtplib

python-2.7