C++中移动构造函数的调用

Question

我有以下代码：

struct Base
{
    std::vector<int> a;
}

struct Derived : public Base
{
    Derived(Base && rhs):
        Base( std::forward<Base>(rhs))
    {
    }
    //some more fields
}
//...
Base a;
Derived b(std::move(a));

调用Derived构造函数是否会导致调用包含在Baseclass中的std::vector的移动构造函数？

Answer 1

是的，Base的implicitly-defined move constructor被调用了，它会对其数据成员a进行move。

For non-union class types (class and struct), the move constructor performs full member-wise move of the object's bases and non-static members, in their initialization order, using direct initialization with an xvalue argument.

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C++中移动构造函数的调用

Calling of move constructor in c++

c++

c++11

move-constructor