Python with 2 稍后继续

Question

我尝试了异常处理并卡在了我的第一个程序中，在这个程序中我的第一个 continue in while 正在工作但第二个没有继续循环

print("hello to divide")
o = "y"
while o == "y":
    try:
        x = int(input("enter first no. = "))
        y = int(input("enter second no. = "))
    except:
        print("please enter numeric value")
        continue
    try:
        z = x/y
        print(str(x) +"/"+str(y)+"="+str(z))
    except:
        print("please do not divide with 0(zero)")
        continue

    finally:
        o = input("do you want to do it again (y/n)? = ")

第二个 except 工作正常，但在打印消息后跳转到 finally 语句

请帮忙???

Answer 1

来自docs:

A finally clause is always executed before leaving the try statement, whether an exception has occurred or not. When an exception has occurred in the try clause and has not been handled by an except clause (or it has occurred in an except or else clause), it is re-raised after the finally clause has been executed. The finally clause is also executed “on the way out” when any other clause of the try statement is left via a break, continue or return statement. A more complicated example:

我很确定你只是想要：

print("hello to divide")
o = "y"
while o == "y":
    try:
        x = int(input("enter first no. = "))
        y = int(input("enter second no. = "))
    except:
        print("please enter numeric value")
        continue
    try:
        z = x/y
        print(str(x) +"/"+str(y)+"="+str(z))
    except:
        print("please do not divide with 0(zero)")
        continue

    o = input("do you want to do it again (y/n)? = ")

Python with 2 稍后继续

Python with 2 continue in a while

python

exception

while-loop

exception-handling

continue