Python 中的生成器和 for 循环
Generators and for loops in Python
所以我有一个生成器函数,看起来像这样。
def generator():
while True:
for x in range(3):
for j in range(5):
yield x
在我加载这个函数并多次调用 "next" 之后,我希望它产生值
0 0 0 0 0 1 1 1 1 1 2 2 2 2 2 0 0 0 0 0 ...
但它始终只产生 0。这是为什么?
>>> execfile("test.py")
>>> generator
<function generator at 0x10b6121b8>
>>> generator().next()
0
>>> generator().next()
0
>>> generator().next()
0
>>> generator().next()
0
>>> generator().next()
0
>>> generator().next()
0
>>> generator().next()
0
generator()
初始化新的生成器对象:
In [4]: generator() is generator() # Creating 2 separate objects
Out[4]: False
然后 generator().next()
从新创建的生成器对象中获取第一个值(0)。
您应该调用 generator
一次:
In [5]: gen = generator() # Storing new generator object, will reuse it
In [6]: [gen.next() for _ in range(6)] # Get first 6 values for demonstration purposes
Out[6]: [0, 0, 0, 0, 0, 1]
注意:generator.next
was removed from Python 3 (PEP 3114) - use the next
function改为:
In [7]: next(gen)
Out[7]: 1
每次调用 generator
您都在创建一个新的生成器对象:
generator().next() # 1st item in 1st generator
generator().next() # 1st item in 2nd generator
创建一个生成器,然后为后续项目调用 next
:
g = generator()
g.next() # 1st item in 1st generator
g.next() # 2nd item in 1st generator
我把它贴在评论里了,我想如果你把这个和问题一起看,你就会发现错误:
with open('my_file.txt', 'r') as f:
print(f.readline()) # `readline` simply reads a single line
with open('my_file.txt', 'r') as f:
print(f.readline())
with open('my_file.txt', 'r') as f:
print(f.readline())
with open('my_file.txt', 'r') as f:
print(f.readline())
不是每次都创建一个新的生成器对象,而是必须创建一次然后使用它直到它被耗尽:
mygen = generator()
mygen.next()
mygen.next()
...
etc
所以我有一个生成器函数,看起来像这样。
def generator():
while True:
for x in range(3):
for j in range(5):
yield x
在我加载这个函数并多次调用 "next" 之后,我希望它产生值
0 0 0 0 0 1 1 1 1 1 2 2 2 2 2 0 0 0 0 0 ...
但它始终只产生 0。这是为什么?
>>> execfile("test.py")
>>> generator
<function generator at 0x10b6121b8>
>>> generator().next()
0
>>> generator().next()
0
>>> generator().next()
0
>>> generator().next()
0
>>> generator().next()
0
>>> generator().next()
0
>>> generator().next()
0
generator()
初始化新的生成器对象:
In [4]: generator() is generator() # Creating 2 separate objects
Out[4]: False
然后 generator().next()
从新创建的生成器对象中获取第一个值(0)。
您应该调用 generator
一次:
In [5]: gen = generator() # Storing new generator object, will reuse it
In [6]: [gen.next() for _ in range(6)] # Get first 6 values for demonstration purposes
Out[6]: [0, 0, 0, 0, 0, 1]
注意:generator.next
was removed from Python 3 (PEP 3114) - use the next
function改为:
In [7]: next(gen)
Out[7]: 1
每次调用 generator
您都在创建一个新的生成器对象:
generator().next() # 1st item in 1st generator
generator().next() # 1st item in 2nd generator
创建一个生成器,然后为后续项目调用 next
:
g = generator()
g.next() # 1st item in 1st generator
g.next() # 2nd item in 1st generator
我把它贴在评论里了,我想如果你把这个和问题一起看,你就会发现错误:
with open('my_file.txt', 'r') as f:
print(f.readline()) # `readline` simply reads a single line
with open('my_file.txt', 'r') as f:
print(f.readline())
with open('my_file.txt', 'r') as f:
print(f.readline())
with open('my_file.txt', 'r') as f:
print(f.readline())
不是每次都创建一个新的生成器对象,而是必须创建一次然后使用它直到它被耗尽:
mygen = generator()
mygen.next()
mygen.next()
...
etc