Apache Isis 构建失败指定未知存储库时使用 ApplicationUser 中的用户作为我实体的属性

Question

我希望我的员工有如下用户

import org.isisaddons.module.security.dom.role.ApplicationRole;
import org.isisaddons.module.security.dom.user.ApplicationUser;
import org.isisaddons.module.security.dom.user.ApplicationUserRepository;

@Column(allowsNull = "true")
@Property(editing = Editing.ENABLED)
@Getter @Setter
private ApplicationUser user;

public List<ApplicationUser> choicesUser() {
    return applicationUserRepository.allUsers();
}

public List<ApplicationRole> getUserRoles() {
    return user!=null? Lists.newArrayList(user.getRoles()):Lists.newArrayList();
}

@Action()
public Employee createUser(
        @ParameterLayout(named = "Username") final String username,
        @ParameterLayout(named = "Password") final Password password,
        @ParameterLayout(named = "Repeat Password") final Password repeatPassword,
        final ApplicationRole initialRole,
        final Boolean enable,
        final String emailAddress) {
    ApplicationUser applicationUser = applicationUserRepository.newLocalUser(username, password, repeatPassword, initialRole, enable, emailAddress);
    this.setUser(applicationUser);
    return this;
}

当我在 IDE 上运行它运行正常，一切都按预期工作，但后来我运行 mvn clean install，它出现如下错误，当我删除上面的代码时，它构建得很好。还有什么我错过的吗？

[INFO] calling @PostConstruct on all domain services
[WARNING] NOT configured
[ERROR]
[ERROR]
[ERROR]
[ERROR] @DomainObject annotation on org.isisaddons.module.security.dom.role.ApplicationRole specifies unknown repository 'org.isisaddons.module.security.dom.role.ApplicationRoleRepository'
[ERROR] @DomainObject annotation on org.isisaddons.module.security.dom.user.ApplicationUser specifies unknown repository 'org.isisaddons.module.security.dom.user.ApplicationUserRepository'
[ERROR]
[ERROR]
[ERROR]
[INFO] calling @PreDestroy on all domain services
[INFO] shutting down org.apache.isis.core.metamodel.specloader.SpecificationLoader@1f041bad
[INFO] ------------------------------------------------------------------------
[INFO] Reactor Summary:
[INFO]
[INFO] Incode QuickStart .................................. SUCCESS [  0.279 s]
[INFO] Incode QuickStart Base Module ...................... SUCCESS [  2.480 s]
[INFO] Employment Module .................................. FAILURE [ 11.695 s]
[INFO] Incode QuickStart App Definition ................... SKIPPED
[INFO] Incode QuickStart Webapp ........................... SKIPPED
[INFO] ------------------------------------------------------------------------
[INFO] BUILD FAILURE
[INFO] ------------------------------------------------------------------------
[INFO] Total time: 15.022 s
[INFO] Finished at: 2017-11-06T11:09:35+07:00
[INFO] Final Memory: 59M/457M
[INFO] ------------------------------------------------------------------------
[ERROR] Failed to execute goal org.apache.isis.tool:isis-maven-plugin:1.15.1:validate (default) on project pApp-module-employment: 2 meta-model problems found. -> [Help 1]
[ERROR]
[ERROR] To see the full stack trace of the errors, re-run Maven with the -e switch.
[ERROR] Re-run Maven using the -X switch to enable full debug logging.
[ERROR]
[ERROR] For more information about the errors and possible solutions, please read the following articles:
[ERROR] [Help 1] http://cwiki.apache.org/confluence/display/MAVEN/MojoFailureException
[ERROR]
[ERROR] After correcting the problems, you can resume the build with the command
[ERROR]   mvn <goals> -rf :pApp-module-employment

请帮助，我也通过关注另一个具有类似问题的问题来删除 pom 上的 !，但它不起作用！！！

Answer 1

simpleapp 原型预先配置为运行 Apache Isis maven 插件的 "validate" 目标，它检查域逻辑中的语义错误（例如孤立的支持方法）。您的堆栈显示了另一个错误：引用不存在的存储库的实体。

来自 AppManifest 的 Maven 插件运行s - 模块简单模块的 pom.xml 中的详细信息 - 但这与用于 bootstrap 的 AppManifest 不同应用：仅针对单个模块。

由于您的 Employee 实体正在引用 ApplicationUser，这导致 ApplicationUser 成为元模型的一部分，因此得到验证。我的猜测是 Maven 插件使用的 AppManifest 没有引用安全模块（具有所需的存储库），这会触发错误。

修复只是将安全模块的声明添加到此 AppManifest 中。您可能只需将您使用的 AppManifest 中的相关行复制到 bootstrap 应用程序。

HTH

Apache Isis 构建失败指定未知存储库时使用 ApplicationUser 中的用户作为我实体的属性

Apache Isis Build Fail specifies unknown repository when use User from ApplicationUser as property of my Entity

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Apache Isis 构建失败指定未知存储库时使用 ApplicationUser 中的用户作为我实体的属性