无法使用 read() 将文件内容读入缓冲区

Question

以下是在 Ubuntu OS 16.04:

上使用 GNU 编译器（g++ 命令）编译的示例代码

#include<iostream>
#include<unistd.h>
#include<fcntl.h>
#include <errno.h>
int main()
{           char* pBuffer;          

            char* storedfilepath = "/home/rtpl/Desktop/ts.mp4";

            std::cout<<"\n Opening file at "<<storedfilepath<<"\n";

            int NumBytesToRead = 1000 ;
            int filedes = open(storedfilepath,O_RDONLY);

            std::cout<<"\n value of error is "<<errno<<"\n";

            std::cout<<"\n value of filedes is "<<filedes;

            if (filedes==0)
            std::cout<<"\n File cannot be opened";
            else
            {
            std::cout<<"\n File opened successfully";
            std::cout<<"\n Now reading file\n"; 

            }

            //if(
            int ret = read(filedes,pBuffer,NumBytesToRead);

            std::cout<<"\n value of error is "<<errno<<"\n";

            if(ret!= -1)
            std::cout<<"\n File read successfully";
            else
            std::cout<<"\n File contents cannot be read";   

            std::cout<<"\nEnd.\n";  

            close(filedes);
            return 0;

}

编译时；我收到此消息：

rtpl@rtpl-desktop:~/Desktop$ g++ -g checkts.cpp
checkts.cpp: In function ‘int main()’:
checkts.cpp:8:27: warning: deprecated conversion from string constant to ‘char*’ [-Wwrite-strings]
    char* storedfilepath = "/home/rtpl/Desktop/ts.mp4";

执行后：

rtpl@rtpl-desktop:~/Desktop$ ./a.out

 Opening file at /home/rtpl/Desktop/ts.mp4

 value of error is 0

 value of filedes is 3
 File opened successfully
 Now reading file

 value of error is 14

 File contents cannot be read
End.

可以找到整个 gdb 调试 here。

问题：为什么当文件是合法的并且编译器没有抛出错误时，却不读取文件内容？

Answer 1

假设您是运行 Linux，errno 值 14 是 EFAULT，或 "bad address"。

给定代码

char* pBuffer;
  .
  .
  .
int ret = read(filedes,pBuffer,NumBytesToRead);

pBuffer 未初始化或以其他方式设置，因此 pBuffer 中的值是不确定的，它肯定没有指向有效地址。

您实际上需要提供一个缓冲区，read() 可以放置读取的数据：

char buffer[ 1024 ]
   .
   .
   .
ssize_t ret = read(filedes,buffer,NumBytesToRead);

可以， 只要 NumBytesToRead 不超过 buffer 中的字节数。 另请注意 ret 现在是正确的 ssize_t 而不是 int.

无法使用 read() 将文件内容读入缓冲区

Unable to read file contents into buffer using read()

c++

file

fcntl

unistd.h