PHP array : 如何将数组分成新的组数组

Question

我有这样的数组结构：

数组(

  [1.1] => INTEGER: 1    
  [1.2] => INTEGER: 2    
  [1.3] => INTEGER: 3    
  [1.4] => INTEGER: 4    
  [1.5] => INTEGER: 5    
  [1.6] => INTEGER: 6    
  [2.1] => STRING: lo    
  [2.2] => STRING: eth0    
  [2.3] => STRING: eth1    
  [2.4] => STRING: wifi0    
  [2.5] => STRING: ath0    
  [2.6] => STRING: br0    
  [3.1] => INTEGER: softwareLoopback(24)    
  [3.2] => INTEGER: ethernetCsmacd(6)    
  [3.3] => INTEGER: ethernetCsmacd(6)    
  [3.4] => INTEGER: ethernetCsmacd(6)    
  [3.5] => INTEGER: ethernetCsmacd(6)    
  [3.6] => INTEGER: ethernetCsmacd(6)

)

我需要像这样将数组单独分成新的组多维数组

数组 (
[0] => 数组（
[0] => 整数：1
[1] => 字符串：lo
[2] => 整数：softwareLoopback(24)
)
.....
)

Answer 1

在 "standard way" 中重新索引您的输入数组（我的意思是索引 0、1、2...）然后您可以编写以下函数

$a = array(1,2,3,21,22,23,31,32,33); // input array - example

function rearrange($a) {
    $r = array();
    $count = count($a) / 3;

    for ($i = 0; $i<$count; $i++) {
        $r[$i] = array(
                0 => $a[$i],
                1 => $a[$i+$count],
                2 => $a[$i+2*$count]
            );
        }
    return ($r);
}  

var_dump($a);
$a = rearrange($a);
var_dump($a);

Answer 2

如果总是 6 组，则分块并转置：

$myArray = [
  '1.1' => 'INTEGER: 1',    
  '1.2' => 'INTEGER: 2',    
  '1.3' => 'INTEGER: 3',    
  '1.4' => 'INTEGER: 4',    
  '1.5' => 'INTEGER: 5',    
  '1.6' => 'INTEGER: 6',    
  '2.1' => 'STRING: lo',    
  '2.2' => 'STRING: eth0',    
  '2.3' => 'STRING: eth1',    
  '2.4' => 'STRING: wifi0',    
  '2.5' => 'STRING: ath0',    
  '2.6' => 'STRING: br0',
  '3.1' => 'INTEGER: softwareLoopback(24)',
  '3.2' => 'INTEGER: ethernetCsmacd(6)',  
  '3.3' => 'INTEGER: ethernetCsmacd(6)',  
  '3.4' => 'INTEGER: ethernetCsmacd(6)',  
  '3.5' => 'INTEGER: ethernetCsmacd(6)',    
  '3.6' => 'INTEGER: ethernetCsmacd(6)',
];

$newArray = call_user_func_array(
    'array_map',
    array_merge(
        array(NULL),
        array_chunk($myArray, 6)
    )
);
var_dump($newArray);

Demo

PHP array : 如何将数组分成新的组数组

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