Thread class 的静态睡眠方法如何在不访问 'this' 引用的情况下工作？

Question

我对静态方法有些困惑。静态方法无法访问 this 引用。 （在Java中，this是引用当前对象的引用。）

当有调用Thread.sleep(millis)时，Threadclass的静态sleep方法如何选择哪个线程休眠？ Thread.sleep(long millis) 是静态方法，无法访问 this 引用。

public class CurrentThreadDemo {
    public static void main(String... args) {

        Thread t = Thread.currentThread();

        System.out.println("Current thread: " + t);

        //change the name of the thread
        t.setName("My thread");
        System.out.println("After name change: " + t);

        try {
            for (int n = 5; n > 0; n--) {
                System.out.println(n);
                Thread.sleep(1000);
            }
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
    }
}

Answer 1

"The Thread.sleep() method essentially interacts with the thread scheduler to put the current thread into a wait state for the required interval."

来源：http://www.javamex.com/tutorials/threads/sleep.shtml

Answer 2

When there is a call to Thread.sleep(millis), how does the static sleep method of Thread class choose to which thread to sleep.

Thread.sleep 的规范是它挂起 当前 线程，即调用 sleep 方法的线程。

Answer 3

When there is a call to Thread.sleep(millis), how does the static sleep method of Thread class choose which thread to sleep?

选择当前线程。调用方法的那个。 Thread.currentThread().

返回的那个

Thread.sleep(long millis) is a static method and does not have access to this reference variable.

我同意。所以？它不需要它。