向右 url 传递时 IOS 中的 alamofire 无效 URL 错误

Question

我想做的是从下面url

获取json数据

https://query.yahooapis.com/v1/public/yql?q=select * from 
   weather.forecast where woeid in (select woeid from geo.places(1) where 
   text='seoul,kr') and u='c'&format=json

如果在浏览器中输入，效果会很好。

但它在 alamofire 上不起作用... 我想是因为 ' mark 如我所见，\ 嵌入说 FATAL invalid url

let rrrr="https://query.yahooapis.com/v1/public/yql?q=select * from weather.forecast where woeid in (select woeid from geo.places(1) where text='seoul,kr') and u='c'&format=json"
        print(rrrr)
        let alamo=Alamofire.request(rrrr,method:.get)
        alamo.responseJSON {

            response in
            if response.data != nil {
                print("not null")
                let json = JSON(data: response.data!)
                print(json)
                print("not null21")
                print(response)
                print("not null12")
                print(response.data!)

日志结果如下

https://query.yahooapis.com/v1/public/yql?q=select * from weather.forecast where woeid in (select woeid from geo.places(1) where text='seoul,kr') and u='c'&format=json
not null
null
not null21
FAILURE: invalidURL("https://query.yahooapis.com/v1/public/yql?q=select * from weather.forecast where woeid in (select woeid from geo.places(1) where text=\'seoul,kr\') and u=\'c\'&format=json")
not null12

Answer 1

正如我所见，您的 URL 字符串包含 select 查询中的 space。

实际上，alamofire 不支持带有 space 的 URL 字符串。尝试将 URL 字符串 spaces 替换为 %20（即编码字符 space）。

或者您可以对 Alamofire 请求使用 URL 编码。

希望对您有所帮助！

Answer 2

我用这个：

enum ConsultOfficesServiceEndpoints : String {
    case getProposedPeople = "aaa/bbb/ccc/%d/"
}

.
.
.

func getProposedPeople(_ name: String, success: @escaping SuccessResponse,failure: @escaping FailureResponse){

    var paramWithSpaces = ""
    var lines = name.components(separatedBy: " ")
    var numlines = lines.count
    var i = 0
    if numlines > 1{
        while i < (numlines - 1) {
            paramWithSpaces = paramWithSpaces + lines[i] + "%20"
            i = i+1
        }
        paramWithSpaces = paramWithSpaces + lines[numlines - 1]
    }else{
        paramWithSpaces = name
    }

    self.GET(withEndpoint: ConsultOfficesServiceEndpoints.getProposedPeople.rawValue.replacingOccurrences(of: "%d", with: paramWithSpaces), params: nil, headers: nil, success: success, failure: failure)
}

向右 url 传递时 IOS 中的 alamofire 无效 URL 错误

Invalid URL Error in alamofire in IOS while passing right url

get

alamofire

ios11