没有 play.api.libs.json.Format 的实例可用于 scala.Predef.Map[java.lang.String、scala.Option[scala.Double]]
No instance of play.api.libs.json.Format is available for scala.Predef.Map[java.lang.String, scala.Option[scala.Double]]
正在尝试为包含选项映射的实体编写 json 格式。它抛出以下错误
Error:(8, 68) No instance of play.api.libs.json.Format is available for scala.Predef.Map[java.lang.String, scala.Option[scala.Double]] in the implicit scope (Hint: if declared in the same file, make sure it's declared before)
代码片段:
import play.api.libs.json.{Json, OFormat}
val a: Map[String, Option[Double]] = Map("a" -> None)
case class Person(x: Map[String, Option[Double]])
object Person {
implicit val personFormat: OFormat[Person] = Json.format[Person]
}
Json.toJson(Person(a))
问题似乎是 play-json 宏无法处理嵌套类型变量:
Map[String, Option[Double]]
您可以使用中间类型包装选项
import play.api.libs.json.{Json, OFormat}
case class OptionDouble(value: Option[Double])
case class Person(x: Map[String, OptionDouble])
implicit val optionDoubleFormat = Json.format[OptionDouble]
implicit val personFormat = Json.format[Person]
val a: Map[String, OptionDouble] = Map("a" -> OptionDouble(None))
Json.toJson(Person(a))
另一种选择是手动编写格式化程序。
您可以定义隐式:
import scala.collection.Map
object Person {
implicit object MapReads extends Reads[Map[String, Option[Double]]] {
def reads(jsValue: JsValue): JsResult[Map[String, Option[Double]]] = jsValue match {
case JsObject(map) => JsSuccess(
map.mapValues {
case JsNumber(d) => Some(d.toDouble)
case _ => None
}
)
case _ => JsError()
}
}
implicit object MapWrites extends Writes[Map[String, Option[Double]]] {
def writes(map: Map[String, Option[Double]]): JsValue =
JsObject(map.mapValues(optd => JsNumber(optd.getOrElse[Double](0.0))))
}
implicit val personFormat: OFormat[Person] = Json.format[Person]
}
println(Json.toJson(Person(a)))//{"x":{"a":0}}
基于.
正在尝试为包含选项映射的实体编写 json 格式。它抛出以下错误
Error:(8, 68) No instance of play.api.libs.json.Format is available for scala.Predef.Map[java.lang.String, scala.Option[scala.Double]] in the implicit scope (Hint: if declared in the same file, make sure it's declared before)
代码片段:
import play.api.libs.json.{Json, OFormat}
val a: Map[String, Option[Double]] = Map("a" -> None)
case class Person(x: Map[String, Option[Double]])
object Person {
implicit val personFormat: OFormat[Person] = Json.format[Person]
}
Json.toJson(Person(a))
问题似乎是 play-json 宏无法处理嵌套类型变量:
Map[String, Option[Double]]
您可以使用中间类型包装选项
import play.api.libs.json.{Json, OFormat}
case class OptionDouble(value: Option[Double])
case class Person(x: Map[String, OptionDouble])
implicit val optionDoubleFormat = Json.format[OptionDouble]
implicit val personFormat = Json.format[Person]
val a: Map[String, OptionDouble] = Map("a" -> OptionDouble(None))
Json.toJson(Person(a))
另一种选择是手动编写格式化程序。
您可以定义隐式:
import scala.collection.Map
object Person {
implicit object MapReads extends Reads[Map[String, Option[Double]]] {
def reads(jsValue: JsValue): JsResult[Map[String, Option[Double]]] = jsValue match {
case JsObject(map) => JsSuccess(
map.mapValues {
case JsNumber(d) => Some(d.toDouble)
case _ => None
}
)
case _ => JsError()
}
}
implicit object MapWrites extends Writes[Map[String, Option[Double]]] {
def writes(map: Map[String, Option[Double]]): JsValue =
JsObject(map.mapValues(optd => JsNumber(optd.getOrElse[Double](0.0))))
}
implicit val personFormat: OFormat[Person] = Json.format[Person]
}
println(Json.toJson(Person(a)))//{"x":{"a":0}}
基于