具有现代语法的可变数组的可变数组

Question

如何编写以下代码：

self.box = [[NSMutableArray alloc] initWithObjects:
                    [NSMutableArray arrayWithObjects:_imageView1,_imageView2,_imageView3,nil],
                    [NSMutableArray arrayWithObjects:_imageView4,_imageView5,_imageView6,nil],
                    [NSMutableArray arrayWithObjects:_imageView7,_imageView8,_imageView9,nil],
                    nil];

使用现代语法？

Answer 1

我会自己回答：对于 NSMutableArray 没有文字语法，所以你必须写：

  self.box = [@[
    [@[ _imageView1, _imageView2, _imageView3 ] mutableCopy],
     [@[ _imageView4, _imageView5, _imageView6 ] mutableCopy],
     [@[ _imageView7, _imageView8, _imageView9 ] mutableCopy]
    ] mutableCopy];

Answer 2

如果您希望使用比您自己的答案更少的括号，您可以使用：

self.box = @[
             @[_imageView1, _imageView2, _imageView3].mutableCopy,
             @[_imageView4, _imageView5, _imageView6].mutableCopy,
             @[_imageView7, _imageView8, _imageView9].mutableCopy
           ].mutableCopy;

具有现代语法的可变数组的可变数组

Mutable array of mutable arrays with modern syntax

objective-c

nsarray