dcast 函数从两个值变量中获取参数

Question

假设我有一个具有以下结构的示例数据框

cars=c("A","A","A","A", "B","B","B","B", "C","C","C","C","A","A","A","A", "B","B","B","B", "C","C","C","C")
vendor=c("d","e","f","g", "d","e","f","g", "d","e","f","g", "d","e","f","g", "d","e","f","g", "d","e","f","g")
state=c(1,1,1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,2,2,2,2)
PS_mean=c(100, 110, 120, 130, 90, 95, 140, 180, 70, 80, 120, 150, 100, 110, 120, 130, 90, 95, 140, 180, 70, 80, 120, 150)
PS_stdv=c(10, 20, 30, 40, 10, 20, 30, 40, 10, 20, 30, 40, 10, 20, 30, 40, 10, 20, 30, 40, 10, 20, 30, 40)
mycars=data.frame(cars, vendor, state, PS_mean, PS_stdv)

我现在想像

一样使用 dcast 应用重塑

mycars_cov<-dcast(setDT(mycars[c('cars','state','PS_mean','PS_stdv')]), cars~state, value.var=c("PS_mean", "PS_stdv"), car_PS_var("PS_mean", "PS_stdv"))

如您所见，函数 "car_PS_var" 是用户定义的，有两个输入

car_PS_var<- function(x,y){
   x<-as.numeric(x)
   y<-as.numeric(y)
   z=sd(x)*sd(y)/mean(x)
   return(z)
}

我不知道如何应用以两个 "value.var" 和一个 return 作为参数的函数。通常使用 dcast 你只能将一个函数应用于一个变量，这就是为什么 car_PS_var("PS_mean", "PS_stdv") 不起作用

在这种形式下，R 会抛出一些错误，因为它不能在 dcast 函数中接受两个输入。

那么我怎样才能正确地做到这一点呢？如果您建议使用任何其他 R 方法来完成任务，也可以

Answer 1

不确定我是否理解你的目标，但从我的解释来看，一种快速而肮脏的方法是先按汽车和状态分组，创建新列，然后 dcast 新数据 table

mycars <- as.data.table(mycars)

temp <- mycars[, .(z = car_PS_var(PS_mean, PS_stdv)),
              by = c("cars", "state")]

dcast(temp, cars ~ state)

   cars        1        2
1:    A 1.449275 1.449275
2:    B 4.325825 4.325825
3:    C 4.545340 4.545340

dcast 函数从两个值变量中获取参数

dcast function taking arguments from two value variables

aggregate

r

dcast