未能在 javascript 中解码 base64
Failed to decode base64 in javascript
我收到 id_token
作为我当前 href 的一部分。它以 base64 编码。我尝试使用 atob(extractedIdToken)
对其进行解码,但出现以下错误:
Failed to execute 'atob' on 'Window': The string to be decoded is not correctly encoded
当我将提取的 id_token
复制并粘贴到我的代码中并转到在线解码站点时,它解码正确。你有什么建议吗?
我一直用这个解码和Base64编码,试试看
var Base64 = {
_keyStr: "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=",
encode: function (e) {
var t = "";
var n, r, i, s, o, u, a;
var f = 0;
e = Base64._utf8_encode(e);
while (f < e.length) {
n = e.charCodeAt(f++);
r = e.charCodeAt(f++);
i = e.charCodeAt(f++);
s = n >> 2;
o = (n & 3) << 4 | r >> 4;
u = (r & 15) << 2 | i >> 6;
a = i & 63;
if (isNaN(r)) {
u = a = 64
} else if (isNaN(i)) {
a = 64
}
t = t + this._keyStr.charAt(s) + this._keyStr.charAt(o) + this._keyStr.charAt(u) + this._keyStr.charAt(a)
}
return t
},
decode: function (e) {
var t = "";
var n, r, i;
var s, o, u, a;
var f = 0;
e = e.replace(/[^A-Za-z0-9+/=]/g, "");
while (f < e.length) {
s = this._keyStr.indexOf(e.charAt(f++));
o = this._keyStr.indexOf(e.charAt(f++));
u = this._keyStr.indexOf(e.charAt(f++));
a = this._keyStr.indexOf(e.charAt(f++));
n = s << 2 | o >> 4;
r = (o & 15) << 4 | u >> 2;
i = (u & 3) << 6 | a;
t = t + String.fromCharCode(n);
if (u != 64) {
t = t + String.fromCharCode(r)
}
if (a != 64) {
t = t + String.fromCharCode(i)
}
}
t = Base64._utf8_decode(t);
return t
},
_utf8_encode: function (e) {
e = e.replace(/rn/g, "n");
var t = "";
for (var n = 0; n < e.length; n++) {
var r = e.charCodeAt(n);
if (r < 128) {
t += String.fromCharCode(r)
} else if (r > 127 && r < 2048) {
t += String.fromCharCode(r >> 6 | 192);
t += String.fromCharCode(r & 63 | 128)
} else {
t += String.fromCharCode(r >> 12 | 224);
t += String.fromCharCode(r >> 6 & 63 | 128);
t += String.fromCharCode(r & 63 | 128)
}
}
return t
},
_utf8_decode: function (e) {
var t = "";
var n = 0;
var r = c1 = c2 = 0;
while (n < e.length) {
r = e.charCodeAt(n);
if (r < 128) {
t += String.fromCharCode(r);
n++
} else if (r > 191 && r < 224) {
c2 = e.charCodeAt(n + 1);
t += String.fromCharCode((r & 31) << 6 | c2 & 63);
n += 2
} else {
c2 = e.charCodeAt(n + 1);
c3 = e.charCodeAt(n + 2);
t += String.fromCharCode((r & 15) << 12 | (c2 & 63) << 6 | c3 & 63);
n += 3
}
}
return t
}
};
感谢大家的回答。我最终使用 java 包将 Base64 解码过程移动到 Java 后端:java.util.Base64.
在我的例子中,问题是编码的字符串应该被视为段。只需用分隔符“.”分隔代码即可。或者无论你的情况是什么。然后,只分别解码不同的部分。这解决了我的问题,我能够使用 window.atob() 进行解码。希望这有帮助。
我收到 id_token
作为我当前 href 的一部分。它以 base64 编码。我尝试使用 atob(extractedIdToken)
对其进行解码,但出现以下错误:
Failed to execute 'atob' on 'Window': The string to be decoded is not correctly encoded
当我将提取的 id_token
复制并粘贴到我的代码中并转到在线解码站点时,它解码正确。你有什么建议吗?
我一直用这个解码和Base64编码,试试看
var Base64 = {
_keyStr: "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=",
encode: function (e) {
var t = "";
var n, r, i, s, o, u, a;
var f = 0;
e = Base64._utf8_encode(e);
while (f < e.length) {
n = e.charCodeAt(f++);
r = e.charCodeAt(f++);
i = e.charCodeAt(f++);
s = n >> 2;
o = (n & 3) << 4 | r >> 4;
u = (r & 15) << 2 | i >> 6;
a = i & 63;
if (isNaN(r)) {
u = a = 64
} else if (isNaN(i)) {
a = 64
}
t = t + this._keyStr.charAt(s) + this._keyStr.charAt(o) + this._keyStr.charAt(u) + this._keyStr.charAt(a)
}
return t
},
decode: function (e) {
var t = "";
var n, r, i;
var s, o, u, a;
var f = 0;
e = e.replace(/[^A-Za-z0-9+/=]/g, "");
while (f < e.length) {
s = this._keyStr.indexOf(e.charAt(f++));
o = this._keyStr.indexOf(e.charAt(f++));
u = this._keyStr.indexOf(e.charAt(f++));
a = this._keyStr.indexOf(e.charAt(f++));
n = s << 2 | o >> 4;
r = (o & 15) << 4 | u >> 2;
i = (u & 3) << 6 | a;
t = t + String.fromCharCode(n);
if (u != 64) {
t = t + String.fromCharCode(r)
}
if (a != 64) {
t = t + String.fromCharCode(i)
}
}
t = Base64._utf8_decode(t);
return t
},
_utf8_encode: function (e) {
e = e.replace(/rn/g, "n");
var t = "";
for (var n = 0; n < e.length; n++) {
var r = e.charCodeAt(n);
if (r < 128) {
t += String.fromCharCode(r)
} else if (r > 127 && r < 2048) {
t += String.fromCharCode(r >> 6 | 192);
t += String.fromCharCode(r & 63 | 128)
} else {
t += String.fromCharCode(r >> 12 | 224);
t += String.fromCharCode(r >> 6 & 63 | 128);
t += String.fromCharCode(r & 63 | 128)
}
}
return t
},
_utf8_decode: function (e) {
var t = "";
var n = 0;
var r = c1 = c2 = 0;
while (n < e.length) {
r = e.charCodeAt(n);
if (r < 128) {
t += String.fromCharCode(r);
n++
} else if (r > 191 && r < 224) {
c2 = e.charCodeAt(n + 1);
t += String.fromCharCode((r & 31) << 6 | c2 & 63);
n += 2
} else {
c2 = e.charCodeAt(n + 1);
c3 = e.charCodeAt(n + 2);
t += String.fromCharCode((r & 15) << 12 | (c2 & 63) << 6 | c3 & 63);
n += 3
}
}
return t
}
};
感谢大家的回答。我最终使用 java 包将 Base64 解码过程移动到 Java 后端:java.util.Base64.
在我的例子中,问题是编码的字符串应该被视为段。只需用分隔符“.”分隔代码即可。或者无论你的情况是什么。然后,只分别解码不同的部分。这解决了我的问题,我能够使用 window.atob() 进行解码。希望这有帮助。