Laravel 5.5 - 检查字符串是否包含确切的单词

Question

在laravel中，我有一个$string和一个$blacklistArray

$string = 'Cassandra is a clean word so it should pass the check';
$blacklistArray = ['ass','ball sack'];

$contains = str_contains($string, $blacklistArray); // true, contains bad word

$contains的结果为真，所以这将被标记为包含黑名单词（这是不正确的）。这是因为下面的名称部分包含 ass

C屁股andra

但是，这是部分匹配，Cassandra 不是坏词，因此不应标记。仅当字符串中的单词完全匹配时，才应对其进行标记。

知道如何完成这个吗？

Answer 1

str_contains() 适用于字符串 - 不适用于数组，但您可以循环它：

$string = 'Cassandra is a clean word so it should pass the check';
$blacklistArray = ['ass','ball sack'];

$flag = false;
foreach ($blacklistArray as $k => $v) {
    if str_contains($string, $v) {
        $flag = true;
        break;
    }
}

if ($flag == true) {
    // someone was nasty
}

Answer 2

$blacklistArray = array('ass','ball sack');

$string = 'Cassandra is a clean word so it should pass the check';



$matches = array();
$matchFound = preg_match_all(
                "/\b(" . implode($blacklistArray,"|") . ")\b/i", 
                $string, 
                $matches
              );

// if it find matches bad words

if ($matchFound) {
  $words = array_unique($matches[0]);
  foreach($words as $word) {

    //show bad words found
    dd($word);
  }

}

Answer 3

文档：https://laravel.com/docs/5.5/helpers#method-str-contains

str_contains函数判断给定字符串是否包含给定值：

$contains = str_contains('This is my name', 'my');

您还可以传递一组值来确定给定的字符串是否包含以下任何值：

$contains = str_contains('This is my name', ['my', 'foo']);

Answer 4

Laravel Str::contains() 方法可以检查作品的价值。别忘了use Illuminate\Support\Str;

适用于 Laravel 7.x

也接受值数组。实例：

$string = 'Cassandra is a clean word so it should pass the check'; $blacklistArray = ['ass','ball sack'];

if(Str::contains($string, $blacklistArray)){return true;}

// returns true

虽然可能不是您的确切要求

Laravel 5.5 - 检查字符串是否包含确切的单词

Laravel 5.5 - Check if string contains exact words

php

laravel

laravel-5

laravel-5.5