隐藏的随机数在 java 中确认了错误的结果

Question

我尝试做的事情有一些问题，但最紧迫的是：

我有一个设置隐藏随机数字的按钮，用户必须尝试找出该数字是什么。我现在的代码如下：

//设置变量

int max = 9;
int min = 0;
int diff = max-min;
int getNum1;
int a;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_guess);

//将Java赋值给XML

final TextView urNum1 = findViewById(R.id.txtUrNum1);
final TextView myNum1 = findViewById(R.id.txtMyNum1);
ImageButton up1 = findViewById(R.id.btnUp1);
ImageButton dn1 = findViewById(R.id.btnDn1);
Button chk = findViewById(R.id.btnCheck);
ImageButton start = findViewById(R.id.btnStartGuess);

//启动随机器

start.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View view) {
        Random rn = new Random();
        urNum1.setText("?");
        a = rn.nextInt(diff+1);
        a += min;
    }
});

//检查匹配

chk.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View view) {
        if (a == 0 && getNum1 == 9) {
            urNum1.setText("0"); }
        else if (a == 1 && getNum1 == 0) {
            urNum1.setText("1"); }
        else if (a == 2 && getNum1 == 1) {
            urNum1.setText("2"); }
        else if (a == 3 && getNum1 == 2) {
            urNum1.setText("3");  }
        else if (a == 4 && getNum1 == 3) {
            urNum1.setText("4"); }
        else if (a == 5 && getNum1 == 4) {
            urNum1.setText("5"); }
        else if (a == 6 && getNum1 == 5) {
            urNum1.setText("6"); }
        else if (a == 7 && getNum1 == 6) {
            urNum1.setText("7"); }
        else if (a == 8 && getNum1 == 7) {
            urNum1.setText("8"); }
        else if (a == 9 && getNum1 == 8) {
            urNum1.setText("9"); }

//增加猜测的数字

up1.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {
                getNum1 = Integer.parseInt(myNum1.getText().toString());
                if (getNum1 == 0) {
                    myNum1.setText("1"); }
                else if (getNum1 == 1 ) {
                    myNum1.setText("2"); }
                else if (getNum1 == 2) {
                    myNum1.setText("3"); }
                else if (getNum1 == 3) {
                    myNum1.setText("4"); }
                else if (getNum1 == 4) {
                    myNum1.setText("5"); }
                else if (getNum1 == 5) {
                    myNum1.setText("6"); }
                else if (getNum1 == 6) {
                    myNum1.setText("7"); }
                else if (getNum1 == 7) {
                    myNum1.setText("8"); }
                else if (getNum1 == 8) {
                    myNum1.setText("9"); }
                else if (getNum1 == 9) {
                    myNum1.setText("0"); }
                });

//递减猜测的数字

dn1.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {
                getNum1 = Integer.parseInt(myNum1.getText().toString());
                if (getNum1 == 0) {
                    myNum1.setText("9"); }
                else if (getNum1 == 9 ) {
                    myNum1.setText("8"); }
                else if (getNum1 == 8) {
                    myNum1.setText("7"); }
                else if (getNum1 == 7) {
                    myNum1.setText("6"); }
                else if (getNum1 == 6) {
                    myNum1.setText("5"); }
                else if (getNum1 == 5) {
                    myNum1.setText("4"); }
                else if (getNum1 == 4) {
                    myNum1.setText("3"); }
                else if (getNum1 == 3) {
                    myNum1.setText("2"); }
                else if (getNum1 == 2) {
                    myNum1.setText("1"); }
                else if (getNum1 == 1) {
                    myNum1.setText("0"); }
            }
        });

我运行遇到的问题是，当按下 up1 时，当我检查它们时，数字往往会匹配，但是当我按 dn1 找到匹配的号码时，我选择的号码较低比匹配的数字多两个。这可能是因为我的编码很复杂，使用 ++ 递增可能会更好，但我似乎也无法让它正常工作。

Answer 1

我自己找到了解决方案，如果有人运行也遇到过这个问题。在我将 myNum 值更改为 incrementing/decrementing 值的代码中，我只检查 'if' 语句的每个条件的当前值，而不更改其中的值。所以无论我检查多少次，它总是一次性的。我的修复：

getNum1 = Integer.parseInt(myNum1.getText().toString());
    if (getNum1 == 0) {
        myNum1.setText("9");
        getNum1 = 9; }
    else if (getNum1 == 9 ) {
        myNum1.setText("8");
        getNum1 = 8; }
    else if (getNum1 == 8) {
        myNum1.setText("7");
        getNum1 = 7; }

等等。

隐藏的随机数在 java 中确认了错误的结果

hidden random number confirms wrong result in java

java

random

increment

decrement

android-studio-3.0