自定义 UIButton @IBDesignable

Question

我创建了一个 UIButton subclass，看起来像一个复选标记。

这是 class：

import UIKit

@IBDesignable
class CheckedButton: UIButton {

    // MARK: - Properties
    @IBInspectable var checked: Bool = false {
        didSet {
            // Toggle the check/uncheck images
            updateImage()
        }
    }


    override init(frame: CGRect) {
        super.init(frame: frame)
        setup()
    }

    required init?(coder aDecoder: NSCoder) {
        super.init(coder: aDecoder)
        setup()
    }

    private func setup() {
        updateImage()
        self.addTarget(self, action: #selector(tapped), for: .touchUpInside)
    }

    private func updateImage() {
        let image = checked ? UIImage(named: "checked") : UIImage(named: "unchecked")
        self.setImage(image, for: .normal)
    }

    /// Called each time the button is tapped, and toggles the checked property
    @objc private func tapped() {
        checked = !checked
        print("New value: \(checked)")
    }  
}

由于我将 checked属性设置为 @IBInspectable，所以我在 IB 中看到了它：

奇怪的是：

如果我将此属性设置为 default，它会在故事板中正确显示

但如果我在检查器中选择 on 或 off，则屏幕不会正确更新。

由于 class 标记为@IBDesignable，我希望按钮外观在 IB 中根据检查器选项卡中为此属性设置的值进行更新。有线索吗？

Answer 1

我的建议是使用其他自定义函数从资产中获取图像：

extension UIImage {
    public static func image(name: String, _ sender: UIView?) -> UIImage? {
        #if TARGET_INTERFACE_BUILDER
            if let sender = sender {
                let bundle = Bundle(for: sender.classForCoder)
                return UIImage(named: name, in: bundle, compatibleWith: sender.traitCollection)
            } else {
                return UIImage(named: name)
            }
        #else
            return UIImage(named: name)
        #endif
    }
}

以你的例子为例：

private func updateImage() {
    let image = checked ? UIImage.image(name: "checked", self) : UIImage(name: "unchecked", self)
   setImage(image, for: .normal)
}

此外，UIButton class 已检查状态，您无需创建自己的子项即可使用 class:

let btn = UIButton(type: .custom)
btn.setImage(UIImage.image(name: "unchecked", self), for: .normal)
btn.setImage(UIImage.image(name: "checked", self), for: .selected)

btn.isSelected = true // change button state between checked and unchecked

Answer 2

UIimage(named:) 方法使用主包，但 Interface Builder 以不同的方式加载资源。

试试这个：

UIImage（命名："checked"，在：bundle，兼容：nil）

 @IBDesignable

 class CheckedButton: UIButton {

 // MARK: - Properties
 @IBInspectable var checked: Bool = false {
     didSet {
         // Toggle the check/uncheck images
         updateImage()
     }
 }


 override init(frame: CGRect) {
     super.init(frame: frame)
     setup()
 }

 required init?(coder aDecoder: NSCoder) {
     super.init(coder: aDecoder)
     setup()
 }

 override func prepareForInterfaceBuilder() {
     super.prepareForInterfaceBuilder()
     setup()
 }

 internal func setup() {
     self.addTarget(self, action: #selector(tapped), for: .touchUpInside)
 }

 private func updateImage() {
     let bundle = Bundle(for: CheckedButton.self)
     let image = checked ? UIImage(named: "checked", in: bundle, compatibleWith:nil) : UIImage(named: "unchecked", in: bundle, compatibleWith:nil)
     self.setBackgroundImage(image, for: .normal)
 }

 /// Called each time the button is tapped, and toggles the checked property
 @objc private func tapped() {
     checked = !checked
     print("New value: \(checked)")
 }

自定义 UIButton @IBDesignable

Custom UIButton @IBDesignable

uibutton

ios

swift

ibdesignable

ibinspectable