Groovy 中函数覆盖和可选参数的奇怪行为

Question

最好用一些代码来解释该行为。在此示例中，从 class y 调用 super.doSomething(t) 而没有可选参数会导致它递归调用自身 (y.doSomething)。这是一个错误还是有解释为什么放弃可选参数并调用 super 导致递归调用。

您可以在这里尝试：https://tio.run/#groovy

class x {
    void doSomething(Integer x, Boolean n=false){
        println("Super ${n}")
    }
}

class y extends x {
    @Override
    void doSomething(Integer t, Boolean q=true){
        println("Sub")
        super.doSomething(t)  //Stack overflow - super.doSomething calls the subclass
        super.doSomething(t, q)  //Works as expected
    }
}

new y().doSomething(4)

Answer 1

下面的代码基本上是为您所拥有的生成的代码，这种表示应该有助于理解它：

class X {
    void doSomething(Integer x) {
        // remember that for an instance of Y, this is
        // going to call doSomething(Integer, Boolean) in
        // the subclass (Y), not this class (X).
        doSomething x, false
    }

    void doSomething(Integer x, Boolean n) {
        println("Super ${n}")
    }
}

class Y extends X {
    void doSomething(Integer t) {
        doSomething t, true
    }
    @Override
    void doSomething(Integer t, Boolean q){
        println("Sub")

        // stack overflow because this calls doSomething(Integer) in
        // the parent class which is going to call
        // doSomething(Integer, Boolean), which will end up right back here
        super.doSomething(t)

        // no stack overflow
        super.doSomething(t, q)
    }
}

Groovy 中函数覆盖和可选参数的奇怪行为

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