Google 地图 python next_page_token 不起作用

Question

我通过 google 地图库发送了一个请求，我得到了 20 个地点的结果。

我的代码看起来像那样

gmaps = googlemaps.Client(key='MY_KEY_IS_HERE')

x = gmaps.places(query=['restaurants', 'bakery', 'cafe', 'food'],location='40.758896, -73.985130',radius=10000)

print len(x['results']) # outputs 20 (which is maximum per 1 page result)

然后我想请求第二页，我想我使用它是正确的。

print gmaps.places(page_token=x['next_page_token'].encode())

它 returns 一个奇怪的错误

    File "/Users/././testz.py", line 15, in <module>
    print gmaps.places(page_token=x['next_page_token'].encode())
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/googlemaps/client.py", line 356, in wrapper
    result = func(*args, **kwargs)
TypeError: places() takes at least 2 arguments (2 given)

我使用 .encode() 因为 'next_page_token' unicode 输出和 googlemaps 需要 'str'.

知道我做错了什么吗？我该如何解决？

Answer 1

如果您再次传递所有参数（除了 page_token），它应该可以工作。请注意，您需要 add a couple of seconds delay 才能在 Google 的服务器上验证令牌。

import googlemaps
import time

k="your key here"

gmaps = googlemaps.Client(key=k)

params = {
    'query': ['restaurants', 'bakery', 'cafe', 'food'],
    'location': (40.758896, -73.985130),
    'radius': 10000
}

x = gmaps.places(**params)
print len(x['results']) # outputs 20 (which is maximum per 1 page result)
print x['results'][0]['name']

params['page_token'] = x['next_page_token']

time.sleep(2)
x1 = gmaps.places(**params)

print len(x1['results'])
print x1['results'][0]['name']

Google 地图 python next_page_token 不起作用

Google maps python next_page_token doesn't work

python

google-maps

google-places-api