SQS 可见性超时锁定整个队列,而不仅仅是特定的消息
SQS visibility timeout locks out the entire queue, instead of just that particular message
我正忙于试验 SQS。据我了解,可见性超时会使其他消费者在该可见性超时期间无法使用消息。不过,根据我的经验,情况似乎并非如此。可见性超时似乎使该队列中的 all 消息不可用。
我有验证这一点的代码:
SendMessageRequest messageRequest = new SendMessageRequest()
.withMessageBody("first one")
.withMessageDeduplicationId(UUID.randomUUID().toString())
.withQueueUrl(queueAddress)
.withMessageGroupId("test1");
sqs.sendMessage(messageRequest);
messageRequest = new SendMessageRequest()
.withMessageBody("second one")
.withMessageDeduplicationId(UUID.randomUUID().toString())
.withQueueUrl(queueAddress)
.withMessageGroupId("test1");
sqs.sendMessage(messageRequest);
ReceiveMessageRequest receiveMessageRequest = new ReceiveMessageRequest(queueAddress);
new Thread(() -> {
System.out.println("t1");
List<Message> messages = sqs.receiveMessage(receiveMessageRequest
.withMaxNumberOfMessages(1)
.withMessageAttributeNames("All")
.withVisibilityTimeout(5)
.withWaitTimeSeconds(1)
).getMessages();
System.out.println(messages.get(0).getBody());
}).start();
new Thread(() -> {
System.out.println("t2");
List<Message> messages = sqs.receiveMessage(receiveMessageRequest
.withMaxNumberOfMessages(1)
.withMessageAttributeNames("All")
.withVisibilityTimeout(5)
.withWaitTimeSeconds(1)
).getMessages();
System.out.println(messages.get(0).getBody());
}).start();
第二个线程抛出 IndexOutOfBoundsException。这是因为它没有可用的消息。这证实可见性超时影响 整个队列 而不仅仅是消息。
不幸的是,这似乎与亚马逊的文档不符。
如果有人知道为什么会这样,或者如果我滥用了 SQS SDK,请告诉我:)
嗯,看来我无法正确阅读 documentation::
When you receive a message with a message group ID, no more messages for the same message group ID are returned unless you delete the message or it becomes visible.
我正忙于试验 SQS。据我了解,可见性超时会使其他消费者在该可见性超时期间无法使用消息。不过,根据我的经验,情况似乎并非如此。可见性超时似乎使该队列中的 all 消息不可用。
我有验证这一点的代码:
SendMessageRequest messageRequest = new SendMessageRequest()
.withMessageBody("first one")
.withMessageDeduplicationId(UUID.randomUUID().toString())
.withQueueUrl(queueAddress)
.withMessageGroupId("test1");
sqs.sendMessage(messageRequest);
messageRequest = new SendMessageRequest()
.withMessageBody("second one")
.withMessageDeduplicationId(UUID.randomUUID().toString())
.withQueueUrl(queueAddress)
.withMessageGroupId("test1");
sqs.sendMessage(messageRequest);
ReceiveMessageRequest receiveMessageRequest = new ReceiveMessageRequest(queueAddress);
new Thread(() -> {
System.out.println("t1");
List<Message> messages = sqs.receiveMessage(receiveMessageRequest
.withMaxNumberOfMessages(1)
.withMessageAttributeNames("All")
.withVisibilityTimeout(5)
.withWaitTimeSeconds(1)
).getMessages();
System.out.println(messages.get(0).getBody());
}).start();
new Thread(() -> {
System.out.println("t2");
List<Message> messages = sqs.receiveMessage(receiveMessageRequest
.withMaxNumberOfMessages(1)
.withMessageAttributeNames("All")
.withVisibilityTimeout(5)
.withWaitTimeSeconds(1)
).getMessages();
System.out.println(messages.get(0).getBody());
}).start();
第二个线程抛出 IndexOutOfBoundsException。这是因为它没有可用的消息。这证实可见性超时影响 整个队列 而不仅仅是消息。
不幸的是,这似乎与亚马逊的文档不符。
如果有人知道为什么会这样,或者如果我滥用了 SQS SDK,请告诉我:)
嗯,看来我无法正确阅读 documentation::
When you receive a message with a message group ID, no more messages for the same message group ID are returned unless you delete the message or it becomes visible.