如何从 python 中的文本文件中按列对项目进行排序

Question

我在包含城市名称和季度收入的文本文件中包含以下项目：

 Atlanta   40 50 23 18
 Denver    56 78 34 11
 Miami     40 34 18 30
 Orlando   55 67 23 11
 Memphis   44 23 56 11
 Boston    55 67 33 23
 Tampa     45 67 54 77

我在对列表中的季度收入进行排序时遇到问题。我现在的程序是这样的。

with open('revenue.txt', 'r') as f:
text = [line.split() for line in f]
print("{:<12}{:<14}{:>10}{:>9}".format("City", "Revenue", "Total", 
"Average"))
for a in text:
    city = a[0]
    revenue = [int(i) for i in a[1:5]]
    total = sum(revenue)
    avg = sum(revenue)/len(revenue)
    print("{:<12}{}{:>6}{:>9.2f}".format(city, revenue, total, avg))

print("\n""Sort the cities by their Quarter 1 revenues.")

print("\n""Sort the cities by their Quarter 3 revenues.")

print("\n""Sort the cities by their total revenues.")

我想弄清楚如何对第一季度、第三季度和总计列进行排序，然后打印与它们关联的城市。例如：

Sort the cities by their Quarter 1 revenues
['Miami','Atlanta','Memphis','Tampa','Boston','Orlando','Denver']
#  [40,40,44,45,55,55,56]

我们将不胜感激。

Answer 1

你可以这样排序：

text = [ 
["Atlanta", 40,50,23,18 ],
["Denver ", 56,78,34,11 ],
["Miami  ", 40,34,18,30 ],
["Orlando", 55,67,23,11 ],
["Memphis", 44,23,56,11 ],
["Boston ", 55,67,33,23 ],
["Tampa  ", 45,67,54,77 ]]


for a in text:
    city = a[0]
    revenue = [int(i) for i in a[1:5]]
    total = sum(revenue)
    avg = sum(revenue)/len(revenue)
  #  print("{:<12}{}{:>6}{:>9.2f}{:>9.2f}{:>9.2f}".format(city, revenue, total, avg))
    a.append(total) # append it to your former array
    a.append(avg)   # append it to your former array


print ("1.Q")
printIt(sorted(text, key=lambda x: x[1])) # sort by 1. Quarter number
print ("2.Q")
printIt(sorted(text, key=lambda x: x[2])) # sort by 2. Quarter number
print ("3.Q")
printIt(sorted(text, key=lambda x: x[3])) # etc.
print ("4.Q")
printIt(sorted(text, key=lambda x: x[4]))
print ("Total")
printIt(sorted(text, key=lambda x: x[5]))
print ("Avg")
printIt(sorted(text, key=lambda x: x[6]))

sorted(..) 将创建一个新的列表对象 - 您可以简单地将其存储到您想要使用的对象中 - 出于演示目的，只需以简单的方式打印它们。

输出：

1.Q
[ ['Atlanta', 40, 50, 23, 18, 131, 32.75], 
  ['Miami  ', 40, 34, 18, 30, 122, 30.5],
  ['Memphis', 44, 23, 56, 11, 134, 33.5], 
  ['Tampa  ', 45, 67, 54, 77, 243, 60.75], 
  ['Orlando', 55, 67, 23, 11, 156, 39.0], 
  ['Boston ', 55, 67, 33, 23, 178, 44.5], 
  ['Denver ', 56, 78, 34, 11, 179, 44.75]]

2.Q
[ ['Memphis', 44, 23, 56, 11, 134, 33.5], 
  ['Miami  ', 40, 34, 18, 30, 122, 30.5],
  ['Atlanta', 40, 50, 23, 18, 131, 32.75],
  ['Orlando', 55, 67, 23, 11, 156, 39.0], 
  ['Boston ', 55, 67, 33, 23, 178, 44.5], 
  ['Tampa  ', 45, 67, 54, 77, 243, 60.75], 
  ['Denver ', 56, 78, 34, 11, 179, 44.75]]

3.Q
[ ['Miami  ', 40, 34, 18, 30, 122, 30.5],
  ['Atlanta', 40, 50, 23, 18, 131, 32.75], 
  ['Orlando', 55, 67, 23, 11, 156, 39.0], 
  ['Boston ', 55, 67, 33, 23, 178, 44.5], 
  ['Denver ', 56, 78, 34, 11, 179, 44.75],
  ['Tampa  ', 45, 67, 54, 77, 243, 60.75], 
  ['Memphis', 44, 23, 56, 11, 134, 33.5]]

4.Q
[ ['Denver ', 56, 78, 34, 11, 179, 44.75], 
  ['Orlando', 55, 67, 23, 11, 156, 39.0],
  ['Memphis', 44, 23, 56, 11, 134, 33.5],
  ['Atlanta', 40, 50, 23, 18, 131, 32.75],
  ['Boston ', 55, 67, 33, 23, 178, 44.5],
  ['Miami  ', 40, 34, 18, 30, 122, 30.5], 
  ['Tampa  ', 45, 67, 54, 77, 243, 60.75]]

Total
[ ['Miami  ', 40, 34, 18, 30, 122, 30.5], 
  ['Atlanta', 40, 50, 23, 18, 131, 32.75],
 ['Memphis', 44, 23, 56, 11, 134, 33.5], 
  ['Orlando', 55, 67, 23, 11, 156, 39.0],
  ['Boston ', 55, 67, 33, 23, 178, 44.5],
  ['Denver ', 56, 78, 34, 11, 179, 44.75], 
  ['Tampa  ', 45, 67, 54, 77, 243, 60.75]]

Avg
[ ['Miami  ', 40, 34, 18, 30, 122, 30.5], 
  ['Atlanta', 40, 50, 23, 18, 131, 32.75],
  ['Memphis', 44, 23, 56, 11, 134, 33.5],
  ['Orlando', 55, 67, 23, 11, 156, 39.0],
  ['Boston ', 55, 67, 33, 23, 178, 44.5],
  ['Denver ', 56, 78, 34, 11, 179, 44.75], 
  ['Tampa  ', 45, 67, 54, 77, 243, 60.75]]

这会将 How to sort a list of objects based on an attribute of the objects? 中显示的内容应用于您的问题。将问题标记为重复。

Answer 2

我会使用字典和列表来提高排序的可读性和代码的可用性。我继续并实现了一个用于打印 table 的函数（因为您在函数中执行了多次）。我还添加了一个字典列表作为您的新数据集。然后我使用函数 sorted 来构建您新组织的列表。

with open('revenue.txt', 'r') as f:
    def print_table(data):
        for value in data:
            print("{city:<12}{revenue}{total:>6}{avg:>9.2f}".format(**value))
    text = [line.split() for line in f]
    data = []
    for a in text:
        revenue = [int(i) for i in a[1:5]]
        data.append({
            'city': a[0],
            'revenue': revenue,
            'total' : sum(revenue),
            'avg' : sum(revenue)/len(revenue)
        })
    print("\n""Original data set.")
    print_table(data)

    print("\n""Sort the cities by their Quarter 1 revenues.")
    print_table(sorted(data,key=lambda a: a['revenue'][0]))   

    print("\n""Sort the cities by their Quarter 3 revenues.")
    print_table(sorted(data,key=lambda a: a['revenue'][2]))   

    print("\n""Sort the cities by their total revenues.")
    print_table(sorted(data,key=lambda a: a['total']))

Answer 3

您可以使用 pandas。就是这么简单:

import pandas

with open('revenue.txt', 'r') as f:
    text = [line.split() for line in f]

df = pandas.DataFrame(text, columns = ["City", "Revenue", "Total", "Average", "Other"])
df_sorted_by_Total = df.sort_values("Total", ascending=True) # Sort by values of the City column

print(df_sorted_by_Total)
print(df_sorted_by_Total["City"].tolist()) # Print City column as list

输出：

      City Revenue Total Average Other
4  Memphis      44    23      56    11
2    Miami      40    34      18    30
0  Atlanta      40    50      23    18
3  Orlando      55    67      23    11
5   Boston      55    67      33    23
6    Tampa      45    67      54    77
1   Denver      56    78      34    11
['Memphis', 'Miami', 'Atlanta', 'Orlando', 'Boston', 'Tampa', 'Denver']

如何从 python 中的文本文件中按列对项目进行排序

How to sort items by column from a text file in python

python

python-3.x

columnsorting