按升序排列数组并删除 objective- c 中的重复值
Sort array in ascending order and remove duplicate values in objective- c
我有一个可水平和垂直滚动的 table。我从 Web 服务 (json) 获取 header 和第一列的数据。我想按升序对数据进行排序，并从 header 和第一列中删除重复数据。为了删除重复值，我使用了以下代码：
-(void) requestFinished: (ASIHTTPRequest *) request
{
NSString *theJSON = [request responseString];
SBJsonParser *parser = [[SBJsonParser alloc] init];
NSMutableArray *jsonDictionary = [parser objectWithString:theJSON error:nil];
headData = [[NSMutableArray alloc] init];
NSMutableArray *head = [[NSMutableArray alloc] init];
leftTableData = [[NSMutableArray alloc] init];
NSMutableArray *left = [[NSMutableArray alloc] init];
rightTableData = [[NSMutableArray alloc]init];
for (NSMutableArray *dictionary in jsonDictionary)
{
Model *model = [[Model alloc]init];
model.cid = [[dictionary valueForKey:@"cid"]intValue];
model.iid = [[dictionary valueForKey:@"iid"]intValue];
model.yr = [[dictionary valueForKey:@"yr"]intValue];
model.val = [dictionary valueForKey:@"val"];
[mainTableData addObject:model];
[head addObject:[NSString stringWithFormat:@"%ld", model.yr]];
[left addObject:[NSString stringWithFormat:@"%ld", model.iid]];
}
NSOrderedSet *orderedSet = [NSOrderedSet orderedSetWithArray:head];
headData = [[orderedSet array] mutableCopy];
// NSSet *set = [NSSet setWithArray:left];
// NSArray *array2 = [set allObjects];
// NSLog(@"%@", array2);
NSOrderedSet *orderedSet1 = [NSOrderedSet orderedSetWithArray:left];
NSMutableArray *arrLeft = [[orderedSet1 array] mutableCopy];
//remove duplicate enteries from header array
[leftTableData addObject:arrLeft];
NSMutableArray *right = [[NSMutableArray alloc]init];
for (int i = 0; i < arrLeft.count; i++)
{
NSMutableArray *array = [[NSMutableArray alloc] init];
for (int j = 0; j < headData.count; j++)
{
/* NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF.iid == %ld", [[arrLeft objectAtIndex:i] intValue]];
NSArray *filteredArray = [mainTableData filteredArrayUsingPredicate:predicate];*/
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF.iid == %ld AND SELF.yr == %ld", [[arrLeft objectAtIndex:i] intValue], [[headData objectAtIndex:j] intValue]];
NSArray *filteredArray = [mainTableData filteredArrayUsingPredicate:predicate];
if([filteredArray count]>0)
{
Model *model = [filteredArray objectAtIndex:0];
[array addObject:model.val];
}
}
[right addObject:array];
}
[rightTableData addObject:right];
}
如何对数组进行升序排序？
请帮忙。
NSSet 仅将非重复对象保留在其内部，以便仅将唯一对象保留在数组中，您可以使用 NSSet as -
假设您有包含重复对象的数组
NSArray *arrayA = @[@"a", @"b", @"a", @"c", @"a"];
NSLog(@"arrayA is: %@", arrayA);
//create a set with the objects from above array as
//the set will not contain the duplicate objects from above array
NSSet *set = [NSSet setWithArray: arrayA];
// create another array from the objects of the set
NSArray *arrayB = [set allObjects];
NSLog(@"arrayB is: %@", set);
上面的输出看起来像：
arrayA is: (
a,
b,
a,
c,
a
)
arrayB is: {(
b,
c,
a
)}
要按升序对可变数组进行排序，您可以使用 NSSortDescriptor 和 sortUsingDescriptors:sortDescriptors。您还需要提供将根据哪个数组进行排序的键。
NSSortDescriptor *sortDescriptor;
sortDescriptor = [[NSSortDescriptor alloc] initWithKey:@"key" ascending:YES];
NSArray *sortDescriptors = [NSArray arrayWithObject:sortDescriptor];
[array sortUsingDescriptors:sortDescriptors];
[sortDescriptor release];
这里有你想要的
//sort description will used to sort array.
NSSortDescriptor *descriptor=[[NSSortDescriptor alloc] initWithKey:@"iid" ascending:YES];
NSArray *descriptors=[NSArray arrayWithObject: descriptor];
NSArray *reverseOrder=[arrLeft sortedArrayUsingDescriptors:descriptors];
reverseOrder是你想要的输出。
还有另一种方法可以对遵循模型的对象进行排序。
NSArray *someArray = /* however you get an array */
NSArray *sortedArray = [someArray sortedArrayUsingComparator:^(id obj1, id obj2) {
NSNumber *rank1 = [obj1 valueForKeyPath:@"iid"];
NSNumber *rank2 = [obj2 valueForKeyPath:@"iid"];
return (NSComparisonResult)[rank1 compare:rank2];
}];
这里 sortedArray 是我们的输出。
您也可以为 yr 键替换相同的东西。
好的，所以你有一个看起来像这样的模型对象...
@interface Model: NSObject
@property NSNumber *idNumber;
@property NSNumber *year;
@property NSString *value;
@end
请注意，我有意使用 NSNumber 而不是 NSInteger，原因会变得很清楚。
目前您正试图在一个地方做很多事情。不要这样做。
创建一个新对象来存储此数据。然后您可以添加方法来获取您需要的数据。看到您在按年份划分的 table 视图中显示，然后每个部分按 idNumber 排序，那么我会做这样的事情...
@interface ObjectStore: NSObject
- (void)addModelObject:(Model *)model;
// standard table information
- (NSInteger)numberOfYears;
- (NSInteger)numberOfIdsForSection:(NSinteger)section;
// convenience methods
- (NSNumber *)yearForSection:(NSInteger)section;
- (NSNumber *)idNumberForSection:(NSInteger)section row:(NSInteger)row;
- (NSArray *)modelsForSection:(NSInteger)section row:(NSInteger)row;
// now you need a way to add objects
- (void)addModelObject:(Model *)model;
@end
现在开始实施。
我们要将所有内容存储在一本字典中。键将是 years，对象将是字典。在这些字典中，键将是 idNumbers，对象将是数组。这些数组将保存模型。
像这样...
{
2010 : {
1 : [a, b, c],
3 : [c, d, e]
},
2013 : {
1 : [g, h, u],
2 : [e, j, s]
}
}
我们还将使用所有便捷方法来执行此操作。
@interface ObjectStore: NSObject
@property NSMutableDictionary *objectDictionary;
@end
@implementation ObjectStore
+ (instancetype)init
{
self = [super init];
if (self) {
self.objectDictionary = [NSMutableDictionary dictionary];
}
return self;
}
+ (NSInteger)numberOfYears
{
return self.objectDictionary.count;
}
+ (NSInteger)numberOfIdsForSection:(NSinteger)section
{
// we need to get the year for this section in order of the years.
// lets create a method to do that for us.
NSNumber *year = [self yearForSection:section];
NSDictionary *idsForYear = self.objectDictionary[year];
return idsForYear.count;
}
- (NSNumber *)yearForSection:(NSInteger)section
{
// get all the years and sort them in order
NSArray *years = [[self.obejctDictionary allKeys] sortedArrayUsingSelector:@selector(compare:)];
// return the correct year
return years[section];
}
- (NSNumber *)idNumberForSection:(NSInteger)section row:(NSInteger)row
{
// same as the year function but for id
NSNumber *year = [self yearForSection:section];
NSArray *idNumbers = [[self.objectDictionary allKeys]sortedArrayUsingSelector:@selector(compare:)];
return idNumbers[row];
}
- (NSArray *)modelsForSection:(NSInteger)section row:(NSInteger)row
{
NSNumber *year = [self yearForSection:section];
NSNumber *idNumber = [self idForSection:section row:row];
return self.objectDictionary[year][idNumber];
}
// now we need a way to add objects that will put them into the correct place.
- (void)addModelObject:(Model *)model
{
NSNumber *modelYear = model.year;
NSNumber *modelId = model.idNumber;
// get the correct storage location out of the object dictionary
NSMutableDictionary *idDictionary = [self.objectDictionary[modelYear] mutableCopy];
// there is a better way to do this but can't think atm
if (!idDictionary) {
idDictionary = [NSMutableDictionary dictionary];
}
NSMutableArray *modelArray = [idDictionary[modelId] mutableCopy];
if (!modelArray) {
modelArray = [NSMutableArray array];
}
// insert the model in the correct place.
[modelArray addObject:model];
idDictionary[modelId] = modelArray;
self.objectDictionary[modelYear] = idDictionary;
}
@end
完成所有这些设置后，您现在可以用这个替换您的复杂函数...
-(void) requestFinished: (ASIHTTPRequest *) request
{
NSString *theJSON = [request responseString];
SBJsonParser *parser = [[SBJsonParser alloc] init];
NSDictionary *jsonDictionary = [parser objectWithString:theJSON error:nil];
for (NSDictionary *dictionary in jsonDictionary)
{
Model *model = [[Model alloc]init];
model.cid = [dictionary valueForKey:@"cid"];
model.idNumber = [dictionary valueForKey:@"iid"];
model.year = [dictionary valueForKey:@"yr"];
model.val = [dictionary valueForKey:@"val"];
[self.objectStore addModelObject:model];
}
}
要获取特定行的模型，只需使用...
[self.objectStore modelsForSection:indexPath.section row:indexPath.row];
要在 table视图委托方法中获取节数...
- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
{
return [self.objectStore numberOfYears];
}
不要乱用视图控制器中的模型。
欢迎使用 MVC 模式。
此处有大量代码，但通过将所有代码放在此处，您可以从 VC.
中删除所有复杂代码
这就是我按升序对 header 数据进行排序并从 header 和最左边的列中删除重复项的方法。希望这会对其他人有所帮助
NSOrderedSet *orderedSet3 = [NSOrderedSet orderedSetWithArray:head3];
headData3 = [[orderedSet3 array] mutableCopy];
[headData3 sortUsingComparator:^NSComparisonResult(NSString *str1, NSString *str2)
{
return [str1 compare:str2 options:(NSNumericSearch)];
}];
NSOrderedSet *orderedSet4 = [NSOrderedSet orderedSetWithArray:left3];
NSMutableArray *arrLeft3 = [[orderedSet4 array] mutableCopy];
[leftTableData3 addObject:arrLeft3];
我有一个可水平和垂直滚动的 table。我从 Web 服务 (json) 获取 header 和第一列的数据。我想按升序对数据进行排序，并从 header 和第一列中删除重复数据。为了删除重复值，我使用了以下代码：
-(void) requestFinished: (ASIHTTPRequest *) request
{
NSString *theJSON = [request responseString];
SBJsonParser *parser = [[SBJsonParser alloc] init];
NSMutableArray *jsonDictionary = [parser objectWithString:theJSON error:nil];
headData = [[NSMutableArray alloc] init];
NSMutableArray *head = [[NSMutableArray alloc] init];
leftTableData = [[NSMutableArray alloc] init];
NSMutableArray *left = [[NSMutableArray alloc] init];
rightTableData = [[NSMutableArray alloc]init];
for (NSMutableArray *dictionary in jsonDictionary)
{
Model *model = [[Model alloc]init];
model.cid = [[dictionary valueForKey:@"cid"]intValue];
model.iid = [[dictionary valueForKey:@"iid"]intValue];
model.yr = [[dictionary valueForKey:@"yr"]intValue];
model.val = [dictionary valueForKey:@"val"];
[mainTableData addObject:model];
[head addObject:[NSString stringWithFormat:@"%ld", model.yr]];
[left addObject:[NSString stringWithFormat:@"%ld", model.iid]];
}
NSOrderedSet *orderedSet = [NSOrderedSet orderedSetWithArray:head];
headData = [[orderedSet array] mutableCopy];
// NSSet *set = [NSSet setWithArray:left];
// NSArray *array2 = [set allObjects];
// NSLog(@"%@", array2);
NSOrderedSet *orderedSet1 = [NSOrderedSet orderedSetWithArray:left];
NSMutableArray *arrLeft = [[orderedSet1 array] mutableCopy];
//remove duplicate enteries from header array
[leftTableData addObject:arrLeft];
NSMutableArray *right = [[NSMutableArray alloc]init];
for (int i = 0; i < arrLeft.count; i++)
{
NSMutableArray *array = [[NSMutableArray alloc] init];
for (int j = 0; j < headData.count; j++)
{
/* NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF.iid == %ld", [[arrLeft objectAtIndex:i] intValue]];
NSArray *filteredArray = [mainTableData filteredArrayUsingPredicate:predicate];*/
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF.iid == %ld AND SELF.yr == %ld", [[arrLeft objectAtIndex:i] intValue], [[headData objectAtIndex:j] intValue]];
NSArray *filteredArray = [mainTableData filteredArrayUsingPredicate:predicate];
if([filteredArray count]>0)
{
Model *model = [filteredArray objectAtIndex:0];
[array addObject:model.val];
}
}
[right addObject:array];
}
[rightTableData addObject:right];
}
如何对数组进行升序排序？
请帮忙。
NSSet 仅将非重复对象保留在其内部，以便仅将唯一对象保留在数组中，您可以使用 NSSet as -
假设您有包含重复对象的数组
NSArray *arrayA = @[@"a", @"b", @"a", @"c", @"a"];
NSLog(@"arrayA is: %@", arrayA);
//create a set with the objects from above array as
//the set will not contain the duplicate objects from above array
NSSet *set = [NSSet setWithArray: arrayA];
// create another array from the objects of the set
NSArray *arrayB = [set allObjects];
NSLog(@"arrayB is: %@", set);
上面的输出看起来像：
arrayA is: (
a,
b,
a,
c,
a
)
arrayB is: {(
b,
c,
a
)}
要按升序对可变数组进行排序，您可以使用 NSSortDescriptor 和 sortUsingDescriptors:sortDescriptors。您还需要提供将根据哪个数组进行排序的键。
NSSortDescriptor *sortDescriptor;
sortDescriptor = [[NSSortDescriptor alloc] initWithKey:@"key" ascending:YES];
NSArray *sortDescriptors = [NSArray arrayWithObject:sortDescriptor];
[array sortUsingDescriptors:sortDescriptors];
[sortDescriptor release];
这里有你想要的
//sort description will used to sort array.
NSSortDescriptor *descriptor=[[NSSortDescriptor alloc] initWithKey:@"iid" ascending:YES];
NSArray *descriptors=[NSArray arrayWithObject: descriptor];
NSArray *reverseOrder=[arrLeft sortedArrayUsingDescriptors:descriptors];
reverseOrder是你想要的输出。
还有另一种方法可以对遵循模型的对象进行排序。
NSArray *someArray = /* however you get an array */
NSArray *sortedArray = [someArray sortedArrayUsingComparator:^(id obj1, id obj2) {
NSNumber *rank1 = [obj1 valueForKeyPath:@"iid"];
NSNumber *rank2 = [obj2 valueForKeyPath:@"iid"];
return (NSComparisonResult)[rank1 compare:rank2];
}];
这里 sortedArray 是我们的输出。
您也可以为 yr 键替换相同的东西。
好的，所以你有一个看起来像这样的模型对象...
@interface Model: NSObject
@property NSNumber *idNumber;
@property NSNumber *year;
@property NSString *value;
@end
请注意，我有意使用 NSNumber 而不是 NSInteger，原因会变得很清楚。
目前您正试图在一个地方做很多事情。不要这样做。
创建一个新对象来存储此数据。然后您可以添加方法来获取您需要的数据。看到您在按年份划分的 table 视图中显示，然后每个部分按 idNumber 排序，那么我会做这样的事情...
@interface ObjectStore: NSObject
- (void)addModelObject:(Model *)model;
// standard table information
- (NSInteger)numberOfYears;
- (NSInteger)numberOfIdsForSection:(NSinteger)section;
// convenience methods
- (NSNumber *)yearForSection:(NSInteger)section;
- (NSNumber *)idNumberForSection:(NSInteger)section row:(NSInteger)row;
- (NSArray *)modelsForSection:(NSInteger)section row:(NSInteger)row;
// now you need a way to add objects
- (void)addModelObject:(Model *)model;
@end
现在开始实施。
我们要将所有内容存储在一本字典中。键将是 years，对象将是字典。在这些字典中，键将是 idNumbers，对象将是数组。这些数组将保存模型。
像这样...
{
2010 : {
1 : [a, b, c],
3 : [c, d, e]
},
2013 : {
1 : [g, h, u],
2 : [e, j, s]
}
}
我们还将使用所有便捷方法来执行此操作。
@interface ObjectStore: NSObject
@property NSMutableDictionary *objectDictionary;
@end
@implementation ObjectStore
+ (instancetype)init
{
self = [super init];
if (self) {
self.objectDictionary = [NSMutableDictionary dictionary];
}
return self;
}
+ (NSInteger)numberOfYears
{
return self.objectDictionary.count;
}
+ (NSInteger)numberOfIdsForSection:(NSinteger)section
{
// we need to get the year for this section in order of the years.
// lets create a method to do that for us.
NSNumber *year = [self yearForSection:section];
NSDictionary *idsForYear = self.objectDictionary[year];
return idsForYear.count;
}
- (NSNumber *)yearForSection:(NSInteger)section
{
// get all the years and sort them in order
NSArray *years = [[self.obejctDictionary allKeys] sortedArrayUsingSelector:@selector(compare:)];
// return the correct year
return years[section];
}
- (NSNumber *)idNumberForSection:(NSInteger)section row:(NSInteger)row
{
// same as the year function but for id
NSNumber *year = [self yearForSection:section];
NSArray *idNumbers = [[self.objectDictionary allKeys]sortedArrayUsingSelector:@selector(compare:)];
return idNumbers[row];
}
- (NSArray *)modelsForSection:(NSInteger)section row:(NSInteger)row
{
NSNumber *year = [self yearForSection:section];
NSNumber *idNumber = [self idForSection:section row:row];
return self.objectDictionary[year][idNumber];
}
// now we need a way to add objects that will put them into the correct place.
- (void)addModelObject:(Model *)model
{
NSNumber *modelYear = model.year;
NSNumber *modelId = model.idNumber;
// get the correct storage location out of the object dictionary
NSMutableDictionary *idDictionary = [self.objectDictionary[modelYear] mutableCopy];
// there is a better way to do this but can't think atm
if (!idDictionary) {
idDictionary = [NSMutableDictionary dictionary];
}
NSMutableArray *modelArray = [idDictionary[modelId] mutableCopy];
if (!modelArray) {
modelArray = [NSMutableArray array];
}
// insert the model in the correct place.
[modelArray addObject:model];
idDictionary[modelId] = modelArray;
self.objectDictionary[modelYear] = idDictionary;
}
@end
完成所有这些设置后，您现在可以用这个替换您的复杂函数...
-(void) requestFinished: (ASIHTTPRequest *) request
{
NSString *theJSON = [request responseString];
SBJsonParser *parser = [[SBJsonParser alloc] init];
NSDictionary *jsonDictionary = [parser objectWithString:theJSON error:nil];
for (NSDictionary *dictionary in jsonDictionary)
{
Model *model = [[Model alloc]init];
model.cid = [dictionary valueForKey:@"cid"];
model.idNumber = [dictionary valueForKey:@"iid"];
model.year = [dictionary valueForKey:@"yr"];
model.val = [dictionary valueForKey:@"val"];
[self.objectStore addModelObject:model];
}
}
要获取特定行的模型，只需使用...
[self.objectStore modelsForSection:indexPath.section row:indexPath.row];
要在 table视图委托方法中获取节数...
- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
{
return [self.objectStore numberOfYears];
}
不要乱用视图控制器中的模型。
欢迎使用 MVC 模式。
此处有大量代码，但通过将所有代码放在此处，您可以从 VC.
中删除所有复杂代码这就是我按升序对 header 数据进行排序并从 header 和最左边的列中删除重复项的方法。希望这会对其他人有所帮助
NSOrderedSet *orderedSet3 = [NSOrderedSet orderedSetWithArray:head3];
headData3 = [[orderedSet3 array] mutableCopy];
[headData3 sortUsingComparator:^NSComparisonResult(NSString *str1, NSString *str2)
{
return [str1 compare:str2 options:(NSNumericSearch)];
}];
NSOrderedSet *orderedSet4 = [NSOrderedSet orderedSetWithArray:left3];
NSMutableArray *arrLeft3 = [[orderedSet4 array] mutableCopy];
[leftTableData3 addObject:arrLeft3];