如何使用 C# 从其他列表创建动态列表
How to create a dynamic list from other lists with C#
我有一个 XML 文件,我正在使用 XmlSerializer
和 StreamReader
阅读,如下所示:
CarCollection cars = null;
XmlSerializer serializer = new XmlSerializer(typeof(CarCollection));
StreamReader reader = new StreamReader(path)
cars = (CarCollection)serializer.Deserialize(reader);
reader.Close();
我的 class CarCollection
正在使用 xml 文件的内容创建列表。
这是我的 classes:
[Serializable()]
public class Car
{
[XmlElement("StockNumber")]
public string StockNumber { get; set; }
[XmlElement("Make")]
public string Make { get; set; }
[XmlElement("Model")]
public string Model { get; set; }
}
[Serializable()]
public class Address
{
[XmlAttribute("Type")]
public string Type { get; set; }
[XmlElement("Name")]
public string Name { get; set; }
[XmlElement("Street")]
public string Street { get; set; }
[XmlElement("City")]
public string City { get; set; }
[XmlElement("State")]
public string State { get; set; }
[XmlElement("Zip")]
public string Zip { get; set; }
[XmlElement("Country")]
public string Country { get; set; }
}
[Serializable()]
[XmlRoot("CarCollection")]
public class CarCollection
{
[XmlAttribute("PurchaseOrderNumber")]
public string PurchaseOrderNumber { get; set; }
[XmlAttribute("OrderDate")]
public string OrderDate { get; set; }
[XmlElement("DeliveryNotes")]
public string DeliveryNotes { get; set; }
public List<Car> Cars;
[XmlElement("Address")]
public List<Address> Address;
}
XML:
<?xml version="1.0" encoding="utf-8"?>
<CarCollection PurchaseOrderNumber="99503" OrderDate="1999-10-20">
<Address Type="Shipping">
<Name>Ellen Adams</Name>
<Street>123 Maple Street</Street>
<City>Mill Valley</City>
<State>CA</State>
<Zip>10999</Zip>
<Country>USA</Country>
</Address>
<Address Type="Billing">
<Name>Tai Yee</Name>
<Street>8 Oak Avenue</Street>
<City>Old Town</City>
<State>PA</State>
<Zip>95819</Zip>
<Country>USA</Country>
</Address>
<DeliveryNotes>Please leave packages in shed by driveway.</DeliveryNotes>
<Cars >
<Car>
<StockNumber>1020</StockNumber>
<Make>Nissan</Make>
<Model>Sentra</Model>
</Car>
<Car>
<StockNumber>1010</StockNumber>
<Make>Toyota</Make>
<Model>Corolla</Model>
</Car>
<Car>
<StockNumber>1111</StockNumber>
<Make>Honda</Make>
<Model>Accord</Model>
</Car>
</Cars>
</CarCollection>
这工作得很好,我得到了我想要的结果,但现在我需要将这 2 个列表和 3 个字段放在一个动态列表中,我该怎么做?
我想知道你为什么想做你描述的事情。
您可以像这样添加 属性 以获得所有内容的列表:
[XmlIgnore]
public List<object> Things
{
get
{
var ret = new List<object>();
if (PurchaseOrderNumber != null)
ret.Add(PurchaseOrderNumber);
if (OrderDate != null)
ret.Add(OrderDate);
if (DeliveryNotes != null)
ret.Add(DeliveryNotes);
if(Cars != null)
ret.AddRange(Cars);
if(Address != null)
ret.Add(Address);
return ret;
}
}
但是没办法设置,因为你怎么知道一个字符串是三个字符串属性中的哪一个。您可以强制它将三个属性放在前三个位置,但那只是令人不快的代码。你可能认为你可以这样做:
[XmlAttribute("PurchaseOrderNumber", typeof(string))]
[XmlAttribute("OrderDate", typeof(string))]
[XmlElement("DeliveryNotes", typeof(string))]
List<object> Things;
但是你不能那样做,因为序列化器有同样的问题,它找到一个字符串,它怎么知道要在 xml 中写入哪个元素或属性?
您可以做的一件事是,如果 Car 和 Address 具有相同的基数 class,您可以这样做:
[XmlElement("Car", typeof(Car))]
[XmlElement("Address", typeof(Address))]
public List<BaseClass> Things {get;set;}
告诉我们更多关于您想要实现的目标,也许有人会提供更多帮助。
我有一个 XML 文件,我正在使用 XmlSerializer
和 StreamReader
阅读,如下所示:
CarCollection cars = null;
XmlSerializer serializer = new XmlSerializer(typeof(CarCollection));
StreamReader reader = new StreamReader(path)
cars = (CarCollection)serializer.Deserialize(reader);
reader.Close();
我的 class CarCollection
正在使用 xml 文件的内容创建列表。
这是我的 classes:
[Serializable()]
public class Car
{
[XmlElement("StockNumber")]
public string StockNumber { get; set; }
[XmlElement("Make")]
public string Make { get; set; }
[XmlElement("Model")]
public string Model { get; set; }
}
[Serializable()]
public class Address
{
[XmlAttribute("Type")]
public string Type { get; set; }
[XmlElement("Name")]
public string Name { get; set; }
[XmlElement("Street")]
public string Street { get; set; }
[XmlElement("City")]
public string City { get; set; }
[XmlElement("State")]
public string State { get; set; }
[XmlElement("Zip")]
public string Zip { get; set; }
[XmlElement("Country")]
public string Country { get; set; }
}
[Serializable()]
[XmlRoot("CarCollection")]
public class CarCollection
{
[XmlAttribute("PurchaseOrderNumber")]
public string PurchaseOrderNumber { get; set; }
[XmlAttribute("OrderDate")]
public string OrderDate { get; set; }
[XmlElement("DeliveryNotes")]
public string DeliveryNotes { get; set; }
public List<Car> Cars;
[XmlElement("Address")]
public List<Address> Address;
}
XML:
<?xml version="1.0" encoding="utf-8"?>
<CarCollection PurchaseOrderNumber="99503" OrderDate="1999-10-20">
<Address Type="Shipping">
<Name>Ellen Adams</Name>
<Street>123 Maple Street</Street>
<City>Mill Valley</City>
<State>CA</State>
<Zip>10999</Zip>
<Country>USA</Country>
</Address>
<Address Type="Billing">
<Name>Tai Yee</Name>
<Street>8 Oak Avenue</Street>
<City>Old Town</City>
<State>PA</State>
<Zip>95819</Zip>
<Country>USA</Country>
</Address>
<DeliveryNotes>Please leave packages in shed by driveway.</DeliveryNotes>
<Cars >
<Car>
<StockNumber>1020</StockNumber>
<Make>Nissan</Make>
<Model>Sentra</Model>
</Car>
<Car>
<StockNumber>1010</StockNumber>
<Make>Toyota</Make>
<Model>Corolla</Model>
</Car>
<Car>
<StockNumber>1111</StockNumber>
<Make>Honda</Make>
<Model>Accord</Model>
</Car>
</Cars>
</CarCollection>
这工作得很好,我得到了我想要的结果,但现在我需要将这 2 个列表和 3 个字段放在一个动态列表中,我该怎么做?
我想知道你为什么想做你描述的事情。
您可以像这样添加 属性 以获得所有内容的列表:
[XmlIgnore]
public List<object> Things
{
get
{
var ret = new List<object>();
if (PurchaseOrderNumber != null)
ret.Add(PurchaseOrderNumber);
if (OrderDate != null)
ret.Add(OrderDate);
if (DeliveryNotes != null)
ret.Add(DeliveryNotes);
if(Cars != null)
ret.AddRange(Cars);
if(Address != null)
ret.Add(Address);
return ret;
}
}
但是没办法设置,因为你怎么知道一个字符串是三个字符串属性中的哪一个。您可以强制它将三个属性放在前三个位置,但那只是令人不快的代码。你可能认为你可以这样做:
[XmlAttribute("PurchaseOrderNumber", typeof(string))]
[XmlAttribute("OrderDate", typeof(string))]
[XmlElement("DeliveryNotes", typeof(string))]
List<object> Things;
但是你不能那样做,因为序列化器有同样的问题,它找到一个字符串,它怎么知道要在 xml 中写入哪个元素或属性?
您可以做的一件事是,如果 Car 和 Address 具有相同的基数 class,您可以这样做:
[XmlElement("Car", typeof(Car))]
[XmlElement("Address", typeof(Address))]
public List<BaseClass> Things {get;set;}
告诉我们更多关于您想要实现的目标,也许有人会提供更多帮助。