如何避免来自 golang 的 "passphrase is too short"

Question

我正在做的是使用

从 golang 程序创建一个 ssh 密钥

exec.Command("ssh-keygen", "-f", "id_rsa", "-t", "rsa", "-P", "\"\"")

但输出失败

exit status 1: Saving key "id_rsa" failed: passphrase is too short (minimum five characters)

如果我在终端中执行命令，它会完美无缺。

Generating public/private rsa key pair.
Your identification has been saved in id_rsa.
Your public key has been saved in id_rsa.pub.
The key fingerprint is:
SHA256:HYixKOtEB42jAr+XNa9uQMZnvmLHa6Sirq+ietWaxzI admin@MacBook-Pro.local
The key's randomart image is:
+---[RSA 2048]----+
|  .o  .          |
|. o... + .       |
|.oooo o . .      |
|o..++ =  . .     |
|. o+ B oS .      |
| o. = + .        |
|  .o O o         |
|. o E X          |
|%*.o Xo.         |
+----[SHA256]-----+

完整代码为：

package main

import (
    "bytes"
    "fmt"
    "os/exec"
)

func main() {
    cmd := exec.Command("ssh-keygen", "-f", "id_rsa", "-t", "rsa", "-P", "\"\"")
    var out bytes.Buffer
    var stderr bytes.Buffer
    cmd.Stdout = &out
    cmd.Stderr = &stderr
    err := cmd.Run()
    if err != nil {
        fmt.Println(fmt.Sprint(err) + ": " + stderr.String())
        return
    }
    fmt.Println("Result: " + out.String())
}

Answer 1

您不需要指定空的 -P 属性，只需简单地使用：

exec.Command("ssh-keygen", "-f", "id_rsa", "-t", "rsa")

如果出于任何原因需要指定空 -P

exec.Command("ssh-keygen", "-f", "id_rsa", "-t", "rsa", "-P", "")

另外，在创建 id_rsa 文件之前，请确保它不存在于您正在创建的目录中，否则您将收到退出错误 1:

如何避免来自 golang 的 "passphrase is too short"

How to avoid "passphrase is too short" from golang

ssh

go

ssh-keygen