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Question

我已经为我的海龟编写了外出狩猎的代码，但是当它们发现猎物时，它们只是简单地吃掉它，无论如何要为它们的成功机会添加一个数学因素，而不是总是 100%

基本上当他们找到猎物时，掷骰子看他们是否可以吃掉它。

to search ;when wolf is hungry 
  set energy  energy  - 1
    fd v-wolf
   if random 600 = 1 ;; frequency of turn
  [ ifelse random 2 = 0 ;; 50:50 chance of left or right
    [ rt 15 ] ;; could add some variation to this with random-normal 45 5
    [ lt 15 ]] ;; so that it samples from a dist with mean 45 SD 5

  ;; check if it can see a prey/food item
  ;; here i think we probably pick one of several possible prey 
  ;; that are detectable randomly using the one-of command.
  ;; We should probably select the nearest one instead, but 
  ;; i cant code that off the top of my head
  if any? prey in-radius smell [set heading towards one-of prey in-radius smell]
  if energy < 0 [die]

end


To eat ;to kill prey and eat it
  let kill one-of prey-here in-radius smell
  ;move-to (need to code it so they move toward prey in a radius
  ;need to code in a variable for success too
  if kill != nobody
    [ask kill [ die ]
      set energy energy + 10000]
end

Answer 1

是的，您可以生成一个随机数，然后仅当该随机数满足特定条件时才执行终止命令。通常的方法是生成一个介于 0 和 1 之间的随机数（在 NetLogo 中是 random-float 1），然后如果你想要 40% 的概率，则执行类似 if random-float 1 < 0.4 [ <what happens> ] 的操作。

回复评论：

to eat
  let kill one-of prey-here in-radius smell
  if kill != nobody and random-float 1 < 0.4
  [ ask kill [ die ]
    set energy energy + 10000 ]
end

请先尝试理解这是在做什么，然后自己思考答案。如果您不理解任何命令的含义，或者任何命令序列的逻辑是什么，请在理解之前不要继续。如果你在代码简单的时候不学习，你将永远无法解决你正在构建的模型中需要做的更困难的事情。

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