如何将 CImg 图像转换为 itkImage?

How can I convert a CImg image to an itkImage?

我有一个 CImg 图像(具有双精度值),在 C++ 中具有以下形式:

CImg<double> image(512,512);
Tcyl.fill(1);

我想使用 ITK 功能来转换此图像。所以我需要将这个 CImg 图像转换成 itkImage 对象。如何转换?

我以前从未使用过 ITK,所以这是一个学习曲线。无论如何,我设法在 CImg 中制作了浮点数的径向渐变,并将其转换为 ITK 图像,然后将其写为浮点数 TIFF.

#include <iostream>
#include <cstdlib>
#define cimg_display 0
#include "CImg.h"
#include "itkImage.h"
#include "itkImportImageFilter.h"
#include "itkImageFileWriter.h"
#include "itkTIFFImageIO.h"

using namespace cimg_library;
using namespace std;

#define W       512
#define H       512

int main() {
    // Create and initialise float image with radial gradient
   cimg_library::CImg<float> img(W,H); 
   cimg_forXY(img,x,y) {img(x,y) = hypot((float)(W/2-x),(float)(H/2-y)); }

   // Now convert CImg image to ITK image
   const unsigned int Dimension = 2;
   typedef itk::Image<float,Dimension>             InputImageType;
   typedef itk::ImportImageFilter<float,Dimension> ImportFilterType;
   ImportFilterType::Pointer importFilter = ImportFilterType::New();

   InputImageType::SizeType imsize;
   imsize[0] = img.width();
   imsize[1] = img.height();

   ImportFilterType::IndexType start;
   start.Fill(0);
   ImportFilterType::RegionType region;
   region.SetIndex(start);
   region.SetSize(imsize);
   importFilter->SetRegion(region);

   const itk::SpacePrecisionType origin[Dimension] = {0.0,0.0};
   importFilter->SetOrigin(origin);

   const itk::SpacePrecisionType spacing[Dimension] = {1.0,1.0};
   importFilter->SetSpacing(spacing);

   // Tell ITK importFilter to take pixels directly from CImg's buffer
   importFilter->SetImportPointer(img.data(),imsize[0]*imsize[1],false);

   // Write result as a TIFF - so I can check it worked
   typedef itk::ImageFileWriter<InputImageType> WriterType;
   typedef itk::TIFFImageIO                  TIFFIOType;
   TIFFIOType::Pointer tiffIO = TIFFIOType::New();
   tiffIO->SetPixelType(itk::ImageIOBase::SCALAR);
   WriterType::Pointer writer = WriterType::New();
   writer->SetFileName("result.tif");
   writer->SetInput(importFilter->GetOutput());
   writer->SetImageIO(tiffIO);
   writer->Update();
}

这是结果(转换为 JPEG 格式):

如果您将 float 更改为 double,它的工作原理是一样的,只是您不能将 double 写入 TIFF,因此最后一位将不起作用。


我一直在搞乱一些,并设法将像素加载到新的 ITK 图像中以供进一步处理,而不是用于输出:

#include <iostream>
#include <cstdlib>
#define cimg_display 0
#include "CImg.h"
#include "itkImage.h"
#include "itkImageRegionIterator.h"

using namespace cimg_library;
using namespace std;

#define W 5
#define H 3

int main() {
    // Create and initialise double image with simple formula
   cimg_library::CImg<double> img(W,H); 
   cimg_forXY(img,x,y) {img(x,y) = (double)x+(10.0*(double)y); }

   // Now convert CImg image to ITK image
   const unsigned int Dimension = 2;
   typedef itk::Image<double,2> ImageType;
   ImageType::Pointer image = ImageType::New();

   ImageType::SizeType size;
   size[0] = img.width();
   size[1] = img.height();

   ImageType::IndexType start;
   start.Fill(0);

   ImageType::RegionType region;
   region.SetSize(size);
   region.SetIndex(start);
   image->SetRegions(region);
   image->Allocate();

   double origin[2];
   origin[0]=0;
   origin[1]=0;
   image->SetOrigin(origin);

   double spacing[2];
   spacing[0]=1;
   spacing[1]=1;
   image->SetSpacing(spacing);

   typedef itk::ImageRegionIterator<ImageType> IteratorType;
   IteratorType it(image,region);
   it.GoToBegin();

   const double* data = img.data();
   while(!it.IsAtEnd()){
      it.Set(*data);
      ++it;
      ++data;
   }

  // Display pixels for checking purposes
  for(unsigned int r = 0; r < H; r++)
  {
      for(unsigned int c = 0; c < W; c++)
      {
          ImageType::IndexType pixelIndex;
          pixelIndex[0] = c;
          pixelIndex[1] = r;
          ImageType::PixelType      pixelValue = image->GetPixel( pixelIndex );
          cout << "Image[" << r << "," << c << "]: " << pixelValue << endl; 
      }
  }
}

示例输出

Image[0,0]: 0
Image[0,1]: 1
Image[0,2]: 2
Image[0,3]: 3
Image[0,4]: 4
Image[1,0]: 10
Image[1,1]: 11
Image[1,2]: 12
Image[1,3]: 13
Image[1,4]: 14
Image[2,0]: 20
Image[2,1]: 21
Image[2,2]: 22
Image[2,3]: 23
Image[2,4]: 24