else 语句中的 while 循环不打印所有答案

While-loop inside else-statement not printing all answers

我得到了这段代码,它链接到我的索引页上的搜索字段:

<?php
   ini_set('display_errors', 2);
   $search = $_GET ['q'];
   $conn = mysqli_connect("localhost", "root", "","release");
   $query    = mysqli_query($conn,"SELECT * FROM game WHERE game_name LIKE '%". $search ."%'");
   $foundnum = mysqli_fetch_assoc($query); 
   $count = count($foundnum['game_name']);


   if ($foundnum == 0) {
      echo "No results found. Either this game doesn't exist, or we have yet to add it. Please contact us!";
      }
         else {
           while($foundnum= mysqli_fetch_assoc($query))
           {
              echo "$count result(s) found!<p>";
              echo"<pre/>";print_r($foundnum['game_name']);
              echo"<pre/>";print_r($foundnum['game_release']);
           }
      }
?>

没有 while 循环一切正常,但是因为一些搜索词(例如 'car')应该同时打印 Project CARS 和 Rise of Incarnates,我需要一个 while-循环。

我也尝试将 while 循环放在 if 语句之前,但这也不起作用。我做错了什么?

我已对您的代码进行了一些更正。请使用以下代码重新验证

我已经使用我的数据库表尝试了代码,它显示了正确的值...

    <?php
    ini_set('display_errors', 1);
    $search = $_GET['q'];
    $conn = mysqli_connect("localhost", "root", "", "release");
    $query = mysqli_query($conn, "SELECT * FROM game WHERE game_name LIKE '%" . $search . "%'");
    $count = mysqli_num_rows($query); // right way to find row count

    if ($count == 0)
    {
        echo "No results found. Either this game doesn't exist, or we have yet to add it. Please contact us!";
    }
    else
    {
        while ($foundnum = mysqli_fetch_assoc($query))
        {
            echo "$count result(s) found!<p>";
            echo"<pre>";
            print_r($foundnum['game_name']);
            echo"</pre><pre>";
            print_r($foundnum['game_code']);
            echo"</pre>";
        }
    }
    ?>

如果您想搜索 insensitively(即忽略大写字母和小写字母),请告诉我。我会更新代码