Spring-data-JPA 外键引用 "UserID" 复合键试图映射到列 "user" 而不是 UserID

Question

我正在尝试在 Spring MVC 应用程序中连接到我的数据库。有两个 table。用户和订单，用户有一个主键列：“userID”，订单有一个来自列的复合键：“userID”和“orderID”，其中 userID 是引用 Users [=32= 中的“userID”列的外键].

这是我的类:

订单：

@Entity
@Table(name = "Orders")
@IdClass(OrderPK.class)
public class Order implements Serializable{

    private static final Long serialVersionUID = 1L;

    @EmbeddedId
    private OrderPK orderPK;

    //other properties
    
    //no args and full args constructor

    //getters and setters

    //toString

}

订单PK：

@Embeddable
public class OrderPK implements Serializable {
    @Column(name = "orderID")
    private Long orderID;

    @ManyToOne
    @JoinColumn(name = "userID")
    private User user;

    public OrderPK() {
    }

    public OrderPK(Long orderID, User user) {
        this.orderID = orderID;
        this.user = user;
    }

    public Long getOrderID() {
        return orderID;
    }

    public void setOrderID(Long orderID) {
        this.orderID = orderID;
    }

    public User getUser() {
        return user;
    }

    public void setUser(User user) {
        this.user = user;
    }

    @Override
    public boolean equals(Object o) {
        if (this == o) return true;
        if (!(o instanceof OrderPK)) return false;
        OrderPK that = (OrderPK) o;
        return Objects.equals(getOrderID(), that.getOrderID()) &&
            Objects.equals(getUser(), that.getUser());
    }

    @Override
    public int hashCode() {
        return Objects.hash(getOrderID(), getUser());
    }
}

用户：

@Entity
@Table(name = "USERS")
public class User implements Serializable {

    private static final long serialVersionUID = 1L;

    @Id
    @SequenceGenerator(name="USER_SEQUENCE", sequenceName="USER_SEQUENCE")
    @GeneratedValue(strategy=GenerationType.SEQUENCE, 
    generator="USER_SEQUENCE")
    @Column(name = "userid")
    private Long userId;

    //other properties
    
    //no args and full args constructor

    //getters and setters

    //toString
}

当我尝试连接到数据库时出现以下异常：

org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in class path resource [org/springframework/boot/autoconfigure/orm/jpa/HibernateJpaAutoConfiguration.class]: Invocation of init method failed; nested exception is org.hibernate.AnnotationException: Unable to find properties (orderID, user) in entity annotated with @IdClass:com.ex.evemarketback.domain.Order

...

Caused by: org.hibernate.AnnotationException: Unable to find properties (orderID, user) in entity annotated with @IdClass:com.ex.evemarketback.domain.Order

有什么建议吗？

Answer 1

由于您正在使用 @EmbeddedId，因此不需要 @IdClass 注释：

@Entity
@Table(name = "Orders")
public class Order implements Serializable{

或者如果你想保留 @IdClass:

// @Embeddable - no need for that
public class OrderPK implements Serializable {
    private Long orderID;
    private Long userId;

    ...
}

实体：

@Entity
@Table(name = "Orders")
@IdClass(OrderPK.class)
public class Order implements Serializable{

    @Id
    @Column(name = "orderID")
    private Long orderID;

    @Id
    @Column(name = "userId", insertable=false, updatable=false)
    private Long userId;

    @ManyToOne
    @JoinColumn(name = "userID")
    private User user;

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