如何在选项卡 activity 中按下后切换回上一个选项卡
How to switch back to previous tab on back pressed in an tabbed activity
我有一个选项卡 activity 1 到 5。如果我从 3 移到 5,然后按下后退键,我想从 5 切换回 3,即按下后退键,我想回到上一个标签。请帮助
使用以下代码实现。(代码也经过测试。)
1.Initialise 一个整数列表和一个布尔值;
private boolean isBackPressed = false;
private boolean isBackPressedOnce = false;
private List<Integer> tabsInBack = new ArrayList<>();
2.Now 你的 onTabSelectedListener 必须像
tabs.setOnTabSelectedListener(new TabLayout.OnTabSelectedListener() {
@Override
public void onTabSelected(TabLayout.Tab tab) {
if(!isBackPressed){
tabsInBack.add(tab.getPosition());}
else {
isBackPressed = false;}
}
@Override
public void onTabUnselected(TabLayout.Tab tab) {
}
@Override
public void onTabReselected(TabLayout.Tab tab) {
}
});
3(i)。现在你的 onBackPressed() 函数必须是,(一个选项卡返回然后关闭)
@Override
public void onBackPressed() {
isBackPressed = true;
if (tabsInBack != null && tabsInBack.size() > 0) {
if (tabs.getSelectedTabPosition() == tabsInBack.get(tabsInBack.size() - 1)) {
tabsInBack.remove(tabsInBack.size() - 1);
}
if (tabsInBack != null && tabsInBack.size() > 0) {
tabs.getTabAt(tabsInBack.get(tabsInBack.size() - 1)).select();
tabsInBack.remove(tabsInBack.size() - 1);
} else {
super.onBackPressed();
}
} else {
super.onBackPressed();
}
}
3(ii)。现在您的 onBackPressed() 函数必须是,(返回所有选定的选项卡然后关闭)
@Override
public void onBackPressed() {
isBackPressed = true;
if (tabsInBack != null && tabsInBack.size() > 0) {
if (tabs.getSelectedTabPosition() == tabsInBack.get(tabsInBack.size() - 1)) {
tabsInBack.remove(tabsInBack.size() - 1);
}
if (tabsInBack != null && tabsInBack.size() > 0) {
tabs.getTabAt(tabsInBack.get(tabsInBack.size() - 1)).select();
tabsInBack.remove(tabsInBack.size() - 1);
if(isBackPressedOnce )
{
super.onBackPressed();
}
else
{
isBackPressedOnce = true;
}
} else {
super.onBackPressed();
}
} else {
super.onBackPressed();
}
}
让我知道它是否有帮助。
这对我有用:)
它的工作原理与 whatsapp
完全一样
@Override
public void onBackPressed() {
//If first tab is open, then quit
if (viewPager.getCurrentItem() == 0) {
super.onBackPressed();
}else {
//If any other tab is open, then switch to first tab
viewPager.setCurrentItem(0);
}
}
我有一个选项卡 activity 1 到 5。如果我从 3 移到 5,然后按下后退键,我想从 5 切换回 3,即按下后退键,我想回到上一个标签。请帮助
使用以下代码实现。(代码也经过测试。)
1.Initialise 一个整数列表和一个布尔值;
private boolean isBackPressed = false;
private boolean isBackPressedOnce = false;
private List<Integer> tabsInBack = new ArrayList<>();
2.Now 你的 onTabSelectedListener 必须像
tabs.setOnTabSelectedListener(new TabLayout.OnTabSelectedListener() {
@Override
public void onTabSelected(TabLayout.Tab tab) {
if(!isBackPressed){
tabsInBack.add(tab.getPosition());}
else {
isBackPressed = false;}
}
@Override
public void onTabUnselected(TabLayout.Tab tab) {
}
@Override
public void onTabReselected(TabLayout.Tab tab) {
}
});
3(i)。现在你的 onBackPressed() 函数必须是,(一个选项卡返回然后关闭)
@Override
public void onBackPressed() {
isBackPressed = true;
if (tabsInBack != null && tabsInBack.size() > 0) {
if (tabs.getSelectedTabPosition() == tabsInBack.get(tabsInBack.size() - 1)) {
tabsInBack.remove(tabsInBack.size() - 1);
}
if (tabsInBack != null && tabsInBack.size() > 0) {
tabs.getTabAt(tabsInBack.get(tabsInBack.size() - 1)).select();
tabsInBack.remove(tabsInBack.size() - 1);
} else {
super.onBackPressed();
}
} else {
super.onBackPressed();
}
}
3(ii)。现在您的 onBackPressed() 函数必须是,(返回所有选定的选项卡然后关闭)
@Override
public void onBackPressed() {
isBackPressed = true;
if (tabsInBack != null && tabsInBack.size() > 0) {
if (tabs.getSelectedTabPosition() == tabsInBack.get(tabsInBack.size() - 1)) {
tabsInBack.remove(tabsInBack.size() - 1);
}
if (tabsInBack != null && tabsInBack.size() > 0) {
tabs.getTabAt(tabsInBack.get(tabsInBack.size() - 1)).select();
tabsInBack.remove(tabsInBack.size() - 1);
if(isBackPressedOnce )
{
super.onBackPressed();
}
else
{
isBackPressedOnce = true;
}
} else {
super.onBackPressed();
}
} else {
super.onBackPressed();
}
}
让我知道它是否有帮助。
这对我有用:) 它的工作原理与 whatsapp
完全一样@Override public void onBackPressed() {
//If first tab is open, then quit
if (viewPager.getCurrentItem() == 0) {
super.onBackPressed();
}else {
//If any other tab is open, then switch to first tab
viewPager.setCurrentItem(0);
}
}