使用增量计算经过的时间
Calculating elapsed time using delta
我一定是在我的代码中犯了一些愚蠢的错误,在我看来这应该可行,但计时器运行得太快了(我想以秒为单位计算剩余时间)。
我的代码:
timeElapsed = 0;
timeLeft = 60;
//delta = time it took to get through one frame (60 fps).
timeElapsed += delta/getFramesPerSecond(); //FPS = 60f
timeLeft -= timeElapsed; //timeLeft starts at 60 (seconds)
timeDisplay = "Time left: " + timeLeft;
我检查过 FPS 始终为 60,我在这里缺少什么?
Delta 样本打印:
0.016969847
0.017038532
0.017123796
0.017026689
0.016969848
0.017059453
0.01697774
0.016987609
0.017073665
0.017035767
0.01708432
timeElapsed+timeLeft
应该是一个常数(因此两者应该在相反的方向上以相同的量变化),但是,您重复将 timeLeft
减少 timeElapsed
在 timeElapsed
中第 1 步的演示示例中,您的代码给出了
timeElapsed timeLeft
0 60
1 59
2 57
3 54
4 50
5 45
6 39
7 32
将代码更改为
timeDelta = delta/getFramesPerSecond();
timeElapsed += timeDelta;
timeLeft -= timeDelta;
timeDisplay = "Time left: " + timeLeft;
我一定是在我的代码中犯了一些愚蠢的错误,在我看来这应该可行,但计时器运行得太快了(我想以秒为单位计算剩余时间)。
我的代码:
timeElapsed = 0;
timeLeft = 60;
//delta = time it took to get through one frame (60 fps).
timeElapsed += delta/getFramesPerSecond(); //FPS = 60f
timeLeft -= timeElapsed; //timeLeft starts at 60 (seconds)
timeDisplay = "Time left: " + timeLeft;
我检查过 FPS 始终为 60,我在这里缺少什么?
Delta 样本打印:
0.016969847
0.017038532
0.017123796
0.017026689
0.016969848
0.017059453
0.01697774
0.016987609
0.017073665
0.017035767
0.01708432
timeElapsed+timeLeft
应该是一个常数(因此两者应该在相反的方向上以相同的量变化),但是,您重复将 timeLeft
减少 timeElapsed
在 timeElapsed
中第 1 步的演示示例中,您的代码给出了
timeElapsed timeLeft
0 60
1 59
2 57
3 54
4 50
5 45
6 39
7 32
将代码更改为
timeDelta = delta/getFramesPerSecond();
timeElapsed += timeDelta;
timeLeft -= timeDelta;
timeDisplay = "Time left: " + timeLeft;