朋友数组中的 strstr() 不起作用

Question

我有这段代码，它从两个用户的 MySQL 中获取数据。当我点击 "remove" 按钮时，它会将用户从朋友数组和结果 return 中删除并返回到数据库中。但它不起作用。请帮助我。

if (@$_POST['removefriend']) {
    $add_friend_check = mysql_query("SELECT friend_array FROM users WHERE username='$user'");
    $get_friend_row = mysql_fetch_assoc($add_friend_check);
    $friend_array = $get_friend_row['friend_array'];

    $friend_array_explode = explode(",", $friend_array);
    $friend_array_count = count($friend_array_explode);

    $add_friend_check_username = mysql_query("SELECT friend_array FROM users WHERE username='$username'");
    $get_friend_row_username = mysql_fetch_assoc($add_friend_check_username);
    $friend_array_username = $get_friend_row_username['friend_array'];

    $friend_array_explode_username = explode(",", $friend_array_username);
    $friend_array_count_username = count($friend_array_explode_username);

    $usernameComma = "," . $username;
    $usernameComma2 = $username . ",";

    $userComma = "," . $user;
    $userComma2 = $user . ",";

    if (strstr($friend_array, $usernameComma)) {
        $friend1 = str_replace("$usernameComma", "", $friend_array);
    } elseif (strstr($friend_array, $usernameComma2)) {
        $friend1 = str_replace("$usernameComma2", "", $friend_array);
    } elseif (strstr($friend_array, $username)) {
        $friend1 = str_replace("$username", "", $friend_array);
    }

    if (strstr($friend_array, $userComma)) {
        $friend2 = str_replace("$userComma", "", $friend_array);
    } elseif (strstr($friend_array, $userComma2)) {
        $friend2 = str_replace("$userComma2", "", $friend_array);
    } elseif (strstr($friend_array, $user)) {
        $friend2 = str_replace("$user", "", $friend_array);
    }

    $removeFriendQuery = mysql_query("UPDATE users SET friend_array='$friend1' WHERE username='$user'");
    $removeFriendQuery_username = mysql_query("UPDATE users SET friend_array='$friend2' WHERE username='$username'");
    echo "Friend was deleted...";
    header("Location: /$username");

Answer 1

您可以通过这种方式大大简化您的代码：

http://sqlfiddle.com/#!9/01c49/1

//somewhere prepare dbo connection like:
$dbh = new PDO("pgsql:host=$host;port=5432;dbname=$db;user=$user;password=$pass");

if (@$_POST['removefriend']) {

$sth = $dbh->prepare("UPDATE users 
SET users.friend_array=
CASE WHEN FIND_IN_SET( :friend ,users.friend_array) > 1 THEN
   REPLACE(users.friend_array , CONCAT(',',:friend),'')
WHEN TRIM(users.friend_array) = :friend THEN
   ''
ELSE REPLACE(users.friend_array , CONCAT(:friend,',','') END
WHERE username= :username 
   AND FIND_IN_SET( :friend ,users.friend_array) >0");
$sth->bindValue(':username', $user, PDO::PARAM_STR);
$sth->bindValue(':friend', $username, PDO::PARAM_STR);
$sth->execute();

$sth->bindValue(':username', $username, PDO::PARAM_STR);
$sth->bindValue(':friend', $user, PDO::PARAM_STR);
$sth->execute();

header("Location: /$username");

但是正如@MarcB 所说，最好重新设计您的数据库。

朋友数组中的 strstr() 不起作用

strstr() in friend array not working

php

mysql

arrays

syntax-error

strstr