Prestashop 订购产品 sql

Question

我在哪里可以找到 Prestashop SQL 查询他们显示按顺序购买的产品的位置。

像这样：

我正在创建一个显示 table 中 100 个订单的自定义页面。如果点击订单，它会显示已订购的产品。我做了一个 sql 查询：

SELECT product_id, product_reference AS kood,product_name AS nimetus,product_quantity AS nr, pl.link_rewrite,psa.quantity as kogukogus,group_concat(ps.product_supplier_reference) as supp_ref, p.location AS asukoht,
         CONCAT(c.link_rewrite,'/',p.id_product,'-',pl.link_rewrite,'.html') link
        FROM ps_order_detail o
        LEFT JOIN ps_product_lang pl on o.product_id = pl.id_product
        LEFT JOIN ps_product p on p.id_product = pl.id_product
        LEFT JOIN ps_stock_available psa on p.id_product = psa.id_product
        LEFT JOIN ps_category_lang c on c.id_category = p.id_category_default
        LEFT JOIN ps_product_supplier ps on p.id_product = ps.id_product
        WHERE pl.id_lang=2 AND c.id_lang=2 AND id_order= '".$q."'
        GROUP BY product_id, kood,nimetus,nr,pl.link_rewrite, kogukogus,asukoht, link

但是当产品有属性时它会复制产品。

在本例中，iButton 有黑色和红色两种颜色（属性）。这个订单只买了一个黑色的iButton，数量是20个，但是显示三排。

我试图解决这个问题，但是我的 sql 查询出现了另一个问题，即当它没有属性时它不会显示任何内容。

SELECT product_id, product_reference AS kood,product_name AS nimetus,product_quantity AS nr, pl.link_rewrite,psa.quantity as kogukogus,group_concat(ps.product_supplier_reference) as supp_ref, p.location AS asukoht,
         CONCAT(c.link_rewrite,'/',p.id_product,'-',pl.link_rewrite,'.html') link
        FROM ps_order_detail o
        JOIN ps_product_lang pl on o.product_id = pl.id_product
        JOIN ps_product p on p.id_product = pl.id_product
        JOIN ps_stock_available psa on p.id_product = psa.id_product
        JOIN ps_category_lang c on c.id_category = p.id_category_default
        JOIN ps_product_supplier ps on p.id_product = ps.id_product
        LEFT JOIN ps_product_attribute pa on p.id_product=pa.id_product
        WHERE pl.id_lang=2 AND pa.id_product_attribute = psa.id_product_attribute AND pa.id_product_attribute =o.product_attribute_id  AND c.id_lang=2 AND id_order= '".$q."'
        GROUP BY product_id, kood,nimetus,nr,pl.link_rewrite, kogukogus,asukoht, link

我该如何解决这个问题？

Answer 1

如果您对结果的特定产品属性不感兴趣，请在查询中使用 SELECT DISTINCT 而不是简单 SELECT

Answer 2

我认为您必须将 2 个 WHERE 条件移动到 JOIN 条件。可能只移动 LEFT JOIN 上的条件就足够了。这应该是结果：

SELECT DISTINCT product_id, product_reference AS kood,product_name AS nimetus,product_quantity AS nr, pl.link_rewrite,psa.quantity as kogukogus,group_concat(ps.product_supplier_reference) as supp_ref, p.location AS asukoht,
         CONCAT(c.link_rewrite,'/',p.id_product,'-',pl.link_rewrite,'.html') link
        FROM ps_order_detail o 
        JOIN ps_product_lang pl on o.product_id = pl.id_product
        JOIN ps_product p on p.id_product = pl.id_product
        JOIN ps_stock_available psa on p.id_product = psa.id_product
        JOIN ps_category_lang c on c.id_category = p.id_category_default
        JOIN ps_product_supplier ps on p.id_product = ps.id_product
        LEFT JOIN ps_product_attribute pa on p.id_product=pa.id_product
                   AND psa.id_product_attribute = pa.id_product_attribute 

        WHERE pl.id_lang=2 AND c.id_lang=2 AND id_order= '".$q."'

Answer 3

感谢您的回答，这确实很愚蠢，但是当从分组依据中删除 kogukogus 时，结果如下：

SELECT product_id, product_reference AS kood,product_name AS nimetus,product_quantity AS nr, pl.link_rewrite,psa.quantity as kogukogus,group_concat(ps.product_supplier_reference) as supp_ref, p.location AS asukoht,
         CONCAT(c.link_rewrite,'/',p.id_product,'-',pl.link_rewrite,'.html') link
        FROM ps_order_detail o
        LEFT JOIN ps_product_lang pl on o.product_id = pl.id_product
        LEFT JOIN ps_product p on p.id_product = pl.id_product
        LEFT JOIN ps_stock_available psa on p.id_product = psa.id_product
        LEFT JOIN ps_category_lang c on c.id_category = p.id_category_default
        LEFT JOIN ps_product_supplier ps on p.id_product = ps.id_product
        WHERE pl.id_lang=2 AND c.id_lang=2 AND id_order= '".$q."'
        GROUP BY product_id, kood,nimetus,nr,pl.link_rewrite,asukoht, link

我以某种方式让它工作了。谢谢@kiks73，您的代码不起作用，但是当我尝试将 group by 添加到您的代码时，我意识到问题出在 group by 上。所以赏金给了你，因为没有人回答任何严肃的问题

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