在 Lua 中打印 table

Question

我在 Lua 中有一个脚本，我需要打印变量 res，但我不知道如何打印。我在另一个函数中得到了函数的结果，我想在那里做 print

function parseCSVLine(line) 
  local res = {}
  local pos = 1
  local sep = ','
  while true do 
     local c = string.sub(line,pos,pos)
     if (c == "") then break end
     if (c == '"') then
        -- quoted value (ignore separator within)
        local txt = ""
        repeat
           local startp,endp = string.find(line,'^%b""',pos) -- Digitos
           txt = txt..string.sub(line,startp+1,endp-1)
           pos = endp + 1
           c = string.sub(line,pos,pos) 
           if (c == '"') then txt = txt..'"' end 
           -- check first char AFTER quoted string, if it is another
           -- quoted string without separator, then append it
           -- this is the way to "escape" the quote char in a quote. example:
           --   value1,"blub""blip""boing",value3  will result in blub"blip"boing  for the middle
        until (c ~= '"')
        table.insert(res,txt)
--        assert(c == sep or c == "")
        pos = pos + 1
     else
        -- no quotes used, just look for the first separator
        local startp,endp = string.find(line,sep,pos)
        if (startp) then 
           table.insert(res,string.sub(line,pos,startp-1))
           pos = endp + 1
        else
           -- no separator found -> use rest of string and terminate
           table.insert(res,string.sub(line,pos))
           break
        end 
     end
  end
  return res
end

例子

local result = parseCSVLine(line)

这里我想打印结果

Answer 1

res in parseCSVLine 似乎是作为列表创建的。所以试试这个：

for i,v in ipairs(result) do print(i,v) end

在 Lua 中打印 table

Print table in Lua

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