Python 3 , Unable to convert datetime stamp to datetime object, TypeError: an integer is required (got type str)

Python 3 , Unable to convert datetime stamp to datetime object, TypeError: an integer is required (got type str)

我正在尝试处理 CSV 格式的时间序列数据并计算时间纪元的数量,对于此示例,纪元 = 1000 毫秒

这里是python代码:

import csv
  import os
  import datetime

    eeg_record = [] 
    path  = "C:\Users\ary\Desktop\nuerosky blink tests\backup\process_from_backup\blink_50px\task_blink40000radious50px_duration_40000.csv"
    """read CSV file"""
    def get_dirs(path_):
        if os.access(path_,os.F_OK and os.R_OK):
            f = open(path_)
            row_counter = 0
            for row in csv.reader(f):
                ##print(row) 
                ##skip the header 
                 if row_counter == 0:
                     row_counter = row_counter + 1
                     continue
                 else:
                     eeg_record.append(row)
            f.close()

    """get the number of epochs based on a epoch size in milliseconds"""
    def get_number_of_epochs(epoch_size_in_milliseconds):
            initial_datetime = datetime.datetime(2000,1,1,0,0,0,0)
            current_datetime = datetime.datetime(2000,1,1,0,0,0,0)
            epoch_counter = 0
            row_counter = 0
            epoch = datetime.timedelta(milliseconds=epoch_size_in_milliseconds)
            for row in eeg_record:
                if row_counter == 0:
                    row_counter =  row_counter + 1
                    initial_datetime = str_to_datetime_(row[1])
                else:    
                    current_datetime = str_to_datetime_(row[1])
                    if  initial_datetime - current_datetime >= epoch:
                        initial_datetime = current_datetime
                        epoch_counter = epoch_counter + 1
            print("counter: ",epoch_counter)

""" covert datetime of this format 2017-10-13 19:22:50:525 to datetime object"""
def  str_to_datetime_(datetime_str):
     return datetime.datetime(datetime_str,'%Y-%m-%d %H:%M:%S:%f')

我 运行 通过 Spyder IDE 并使用 Python 3.6.2

我的输入:

 get_number_of_epochs(1000)

数据示例:

Time_Stamp_In_Milli_Secs,Time_Stamp_Formatted,Raw,A,B,C,D,Class_Stimulia
1.50795E+12,2017-10-13 19:22:13:249,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:249,55,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:250,55,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:250,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:250,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:250,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:250,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:251,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:251,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:251,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:251,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:251,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:251,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:252,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:252,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:252,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:252,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:252,55,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:253,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:253,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:266,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:266,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:266,55,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:267,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:267,55,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:267,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:267,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:267,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:268,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:268,53,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:280,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:280,54,-1,0,0,-1,NO_STIMULIA
1.50795E+12,2017-10-13 19:22:13:280,54,-1,0,0,-1,NO_STIMULIA

错误:

  File "<ipython-input-235-fac5a2a567a4>", line 33, in get_number_of_epochs
    initial_datetime = str_to_datetime_(row[1])

  File "<ipython-input-235-fac5a2a567a4>", line 45, in str_to_datetime_
    return datetime.datetime(datetime_str,'%Y-%m-%d %H:%M:%S:%f')

TypeError: an integer is required (got type str)

如何在我的代码中使用当前 API 修复此错误?

我想你要找的是

datetime.datetime.strptime(datetime_str, '%Y-%m-%d %H:%M:%S:%f')

标准 datetime 构造函数看起来像

datetime.datetime(year: int, month: int, day: int, hour: int, minute: int, second: int, millisecond: int, tzinfo: datetime.tzinfo)

执行以下操作并查看:

  1. 将您的 str_to_datetime_ 函数更改为以下内容

    def  str_to_datetime_(datetime_str):
        return datetime.datetime.strptime(datetime_str, '%Y-%m-%d %H:%M:%S:%f')