将 Excel 范围导出到 .txt 文件时出现额外空行
Getting an Extra Empty line when exporting Excel Range to .txt file
我正在尝试将 Excel 范围复制到 .txt 文件。
导出成功,有一处异常,最后多了一个“extra”空行。
我已经阅读并测试了 SO(和其他网站)上的许多解决方案,但仍然没有成功。
我的代码(相关部分)
' === Export to the .txt file ===
Dim TxtFileName As String, lineText As String
TxtFileName = ThisWorkbook.Path & "\Inv_" & Format(Date, "yyyymmdd") & ".txt"
Open TxtFileName For Output As #1
With StockSht
For i = 1 To LastRow
For j = 1 To 3
If j = 3 Then
lineText = lineText & .Cells(i, j).Value2
Else ' j = 1 or 2
lineText = lineText & .Cells(i, j).Value2 & vbTab
End If
Next j
Print #1, lineText
lineText = ""
Next i
End With
Close #1
我的 StockSht
(工作表对象)和 LastRow
已正确定义,并且正在获取它们的值。
导出的 .txt 文件结尾的屏幕截图
尝试在最后一个打印行上使用 ;
。
' === Export to the .txt file ===
Dim TxtFileName As String, lineText As String
TxtFileName = ThisWorkbook.Path & "\Inv_" & Format(Date, "yyyymmdd") & ".txt"
Open TxtFileName For Output As #1
With StockSht
For i = 1 To LastRow
For j = 1 To 3
If j = 3 Then
lineText = lineText & .Cells(i, j).Value2
Else ' j = 1 or 2
lineText = lineText & .Cells(i, j).Value2 & vbTab
End If
Next j
If i = LastRow Then
Print #1, lineText;
Else
Print #1, lineText
End if
lineText = ""
Next i
End With
Close #1
您可以在 Print
语句中使用分号来控制插入点(即防止在最后一行换行)。
MSDN页面上的相关位:
Use a semicolon to position the insertion point immediately after the last character displayed.
我测试了这段代码:
Sub PrintTest()
Dim lng As Long
Open "C:\foo3.txt" For Output As #1
For lng = 1 To 10
If lng < 10 Then
Print #1, "foo" & lng
Else
Print #1, "foo" & lng; '<-- semi-colon prevents the newline
End If
Next lng
Close #1
End Sub
所以我会像下面这样更新您的代码(未测试):
' === Export to the .txt file ===
Dim TxtFileName As String, lineText As String
TxtFileName = ThisWorkbook.Path & "\Inv_" & Format(Date, "yyyymmdd") & ".txt"
Open TxtFileName For Output As #1
With StockSht
For i = 1 To LastRow
For j = 1 To 3
If j = 3 Then
lineText = lineText & .Cells(i, j).Value2
Else ' j = 1 or 2
lineText = lineText & .Cells(i, j).Value2 & vbTab
End If
Next j
'--- new bit: check for i against LastRow and add the semicolon on last row
If i <> LastRow Then
Print #1, lineText
Else
Print #1, lineText; '<-- semi colon keeps insertion point at end of line
End If
lineText = ""
Next i
End With
Close #1
我正在尝试将 Excel 范围复制到 .txt 文件。
导出成功,有一处异常,最后多了一个“extra”空行。
我已经阅读并测试了 SO(和其他网站)上的许多解决方案,但仍然没有成功。
我的代码(相关部分)
' === Export to the .txt file ===
Dim TxtFileName As String, lineText As String
TxtFileName = ThisWorkbook.Path & "\Inv_" & Format(Date, "yyyymmdd") & ".txt"
Open TxtFileName For Output As #1
With StockSht
For i = 1 To LastRow
For j = 1 To 3
If j = 3 Then
lineText = lineText & .Cells(i, j).Value2
Else ' j = 1 or 2
lineText = lineText & .Cells(i, j).Value2 & vbTab
End If
Next j
Print #1, lineText
lineText = ""
Next i
End With
Close #1
我的 StockSht
(工作表对象)和 LastRow
已正确定义,并且正在获取它们的值。
导出的 .txt 文件结尾的屏幕截图
尝试在最后一个打印行上使用 ;
。
' === Export to the .txt file ===
Dim TxtFileName As String, lineText As String
TxtFileName = ThisWorkbook.Path & "\Inv_" & Format(Date, "yyyymmdd") & ".txt"
Open TxtFileName For Output As #1
With StockSht
For i = 1 To LastRow
For j = 1 To 3
If j = 3 Then
lineText = lineText & .Cells(i, j).Value2
Else ' j = 1 or 2
lineText = lineText & .Cells(i, j).Value2 & vbTab
End If
Next j
If i = LastRow Then
Print #1, lineText;
Else
Print #1, lineText
End if
lineText = ""
Next i
End With
Close #1
您可以在 Print
语句中使用分号来控制插入点(即防止在最后一行换行)。
MSDN页面上的相关位:
Use a semicolon to position the insertion point immediately after the last character displayed.
我测试了这段代码:
Sub PrintTest()
Dim lng As Long
Open "C:\foo3.txt" For Output As #1
For lng = 1 To 10
If lng < 10 Then
Print #1, "foo" & lng
Else
Print #1, "foo" & lng; '<-- semi-colon prevents the newline
End If
Next lng
Close #1
End Sub
所以我会像下面这样更新您的代码(未测试):
' === Export to the .txt file ===
Dim TxtFileName As String, lineText As String
TxtFileName = ThisWorkbook.Path & "\Inv_" & Format(Date, "yyyymmdd") & ".txt"
Open TxtFileName For Output As #1
With StockSht
For i = 1 To LastRow
For j = 1 To 3
If j = 3 Then
lineText = lineText & .Cells(i, j).Value2
Else ' j = 1 or 2
lineText = lineText & .Cells(i, j).Value2 & vbTab
End If
Next j
'--- new bit: check for i against LastRow and add the semicolon on last row
If i <> LastRow Then
Print #1, lineText
Else
Print #1, lineText; '<-- semi colon keeps insertion point at end of line
End If
lineText = ""
Next i
End With
Close #1