获取一个单元内矩阵值之间的差异

Question

我有一个 nxm 列表的列表，我正在尝试计算一个单元内的每个值 i 和每个其他值 j 之间的差异，并将其添加到新列表中。我如何才能在 Python 中做到这一点？

Answer 1

让我们定义一个测试矩阵和一个函数来获取单元格的所有邻居：

m = [[i for i in range(10)] for i in range(10)]

# Size of "board"
X = len(m)
Y = len(m[0])

neighbors = lambda x, y : [(x2, y2) for x2 in range(x-1, x+2)
                               for y2 in range(y-1, y+2)
                               if (-1 < x <= X and
                                   -1 < y <= Y and
                                   (x != x2 or y != y2) and
                                   (0 <= x2 <= X) and
                                   (0 <= y2 <= Y))]

然后计算差异：

def get_differences(point, neigh, m):
    px, py = point
    return [m[px][py] - m[nx][ny] for nx, ny in neigh]

并测试两者的单点：

point = (1,1)
print('Neighbours: ', neighbors(*(point)))
print('Differences: ')
print(get_differences(point, neighbors(*(point)), m))

优雅的neighbors函数部分摘自this post.

获取一个单元内矩阵值之间的差异

Get differences between matrix values within one unit

python

operations

matrix