.php 如何显示我可以更改并存储在我的目录中的图像

Question

你好，我试图在 php 中实现一些非常简单的事情。我想要一个显示图像的页面，我可以通过发送新图像来更改该图像，并且该图像与我的 php 存放在同一文件夹中。因此，当我打开我的页面时，我将上传最后一张图片。理想情况下，我可以像 croppie 那样裁剪它 (https://foliotek.github.io/Croppie/)，但我想了解这些步骤，所以让我们保持简单，裁剪将在以后使用。

到目前为止，允许我上传图片的代码是

upload.php:

<?php
$target_dir = "uploads/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadOk = 1;
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
// Check if image file is a actual image or fake image
if(isset($_POST["submit"])) {
    $check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
    if($check !== false) {
        echo "File is an image - " . $check["mime"] . ".";
        $uploadOk = 1;
    } else {
        echo "File is not an image.";
        $uploadOk = 0;
    }
}
// Check if file already exists
if (file_exists($target_file)) {
    echo "Sorry, file already exists.";
    $uploadOk = 0;
}
// Check file size
if ($_FILES["fileToUpload"]["size"] > 500000) {
    echo "Sorry, your file is too large.";
    $uploadOk = 0;
}
// Allow certain file formats
if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg"
&& $imageFileType != "gif" ) {
    echo "Sorry, only JPG, JPEG, PNG & GIF files are allowed.";
    $uploadOk = 0;
}
// Check if $uploadOk is set to 0 by an error
if ($uploadOk == 0) {
    echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} else {
    if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) {
        echo "The file ". basename( $_FILES["fileToUpload"]["name"]). " has been uploaded.";
    } else {
        echo "Sorry, there was an error uploading your file.";
    }
}
?>

和index.html

<form action="upload.php" method="post" enctype="multipart/form-data">
    Select image to upload:
    <input type="file" name="fileToUpload" id="fileToUpload">
    <input type="submit" value="Upload Image" name="submit">
</form>

所以我不仅想预览显示的图像，而且我还想只储存一张具有特定 ID 的图像（如果您想知道为什么，那是因为它会直接进入 indesign，无论如何。 ..)

感谢大家的帮助！！！

Answer 1

首先在index.html中创建以下代码

<?php

$path = 'i/';
$tmp_path = 'tmp/';
$types = array('image/gif', 'image/png', 'image/jpeg');
$size = 1024000;

if ($_SERVER['REQUEST_METHOD'] == 'POST')
{
 if (!in_array($_FILES['picture']['type'], $types))
  die('wrong type. <a href="?">maybe another file?</a>');

 // Check size
 if ($_FILES['picture']['size'] > $size)
  die('BIG. <a href="?">maybe another file?</a>');

 // Upload
 if (!@copy($_FILES['picture']['tmp_name'], $path . $_FILES['picture']['name']))
  echo 'wrong';
 else
 echo 'good <a href="' . $path . $_FILES['picture']['name'] . '">see</a> ' ;
}

?>
<!DOCTYPE html>
<html>
 <head>
  <title></title>
 </head>
 <body>
  <form method="post" enctype="multipart/form-data">
 <input type="file" name="picture">
 <input type="submit" value="Upload">
  </form>
 </body>
</html>

这是一坨屎代码。尝试分享来自 html

的 php 代码

http://php.net/manual/en/features.file-upload.post-method.php

Answer 2

我找到的解决方案灵感来自该页面 How to upload & Save Files with Desired name

<form action='' method='POST' enctype='multipart/form-data'>
<input type='file' name='userFile'><br>
<input type='submit' name='upload_btn' value='upload'>
</form>

<?php
$info = pathinfo($_FILES['userFile']['name']);
$ext = $info['extension']; // get the extension of the file
$newname = "newname.".$ext; 

$target = 'images/'.$newname;
move_uploaded_file( $_FILES['userFile']['tmp_name'], $target);
?>

<img src="images/newname.png">

干净高效！效果不错！

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