使用 boost::lexical_cast 将 UUID 转换为字符串时出现 Boost 编译错误

Question

我有这段代码，它基于 SO 中的几篇文章：

boost::uuids::uuid uuid = boost::uuids::random_generator()();
auto uuidString= boost::lexical_cast<std::string>(uuid);

但是当我编译这段代码时，出现了这个错误：

Source type is neither std::ostream`able nor std::wostream`able     C:\Local\boost\boost\lexical_cast\detail\converter_lexical.hpp  

如何解决这个错误？

Answer 1

你可以试试：

std::stringstream ss;
std::string       uuidStr;

boost::uuids::uuid uuid = boost::uuids::random_generator()();

ss << uuid;
ss >> uuidStr;

---

Documentation 状态：

Stream Operators

The standard input and output stream operators << and >> are provided by including boost/uuid/uuid_io.hpp. The string representation of a uuid is hhhhhhhh-hhhh-hhhh-hhhh-hhhhhhhhhhhh where h is a hexidecimal digit.

boost::uuids::uuid u1; // initialize uuid

std::stringstream ss;
ss << u1;

boost::uuids::uuid u2;
ss >> u2;

assert(u1, u2);

但是 lexical_cast 应该也能正常工作。

也许您应该检查 uuid 实际包含的内容，以确定生成的 uuid.

是否有问题

还有：

boost::uuids::uuid u; // initialize uuid

std::string s1 = to_string(u);

根据文档，应该稍微快一些。

Answer 2

你错过了包含，我猜：

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#include <boost/lexical_cast.hpp>
#include <boost/uuid/uuid_io.hpp>
#include <boost/uuid/uuid.hpp>
#include <boost/uuid/random_generator.hpp>

int main() {
    boost::uuids::uuid uuid = boost::uuids::random_generator()();
    auto uuidString = boost::lexical_cast<std::string>(uuid);
}