是否可以解构出 ValueTuple 参数？

Question

是否可以解构不是从方法返回但作为输出参数的元组？我不确定我是否正确表达了自己，甚至使用了正确的术语，所以这里有一些例子：

void OutMethod(out (int aNumber, string someText) output)
    => output = (15, "yo");

void Usage()
{
    {
        // Works, of course.
        OutMethod(out var tuple);

        // But *slightly* aesthetically unappealing to use.
        var usage = $"{tuple.someText}: {tuple.aNumber}";
    }

    {
        // Would be awesome, but doesn't work.
        OutFunction(out var(number, text));
    }

    {
        // Would be awesome too, but doesn't work.
        OutFunction(out (var number, var text));
    }

    {
        // This doesn't work either.
        OutFunction((out var number, out var text));
    }

    {
        // Not even this.
        OutFunction((out int number, out string text));
    }

    {
        // Or this.
        OutMethod(out (int number, string text));
    }

    {
        // Or this.
        int number;
        string text;
        OutMethod(out (number, text));
    }
}

顺便说一句，不是抱怨。只是想知道我是否遗漏了什么。

Answer 1

这目前是不可能的。 Further, according to this comment on the CSharplang github repo:

This was something that we took up in the LDM [Language Design Meetings] when we were triaging and decided against doing, at least for the near future...

因此它可能会在未来一段时间内保持 "isn't possible"。

Answer 2

虽然另一个答案是正确的，因为它不能作为函数调用的一部分在一行中完成，但您当然可以根据需要手动解构 out 参数：

OutMethod(out var tuple);
(int aNumber, string someText) = tuple;
var usage = $"{someText}: {aNumber}";

这至少会解决您的使用问题。

是否可以解构出 ValueTuple 参数？

Is it possible to deconstruct out ValueTuple parameters?

c#

c#-7.0