JSON 获取在真实主机中不能正常工作,但在本地主机中工作
JSON fetch dosen't work correctly in real host but work in localhost
我的免费主机中有这个 json
:http://alibhm.epizy.com/fetch_turbine2.php
如您所见,如果 运行 在浏览器中执行此操作并获取两个参数,则获取工作正常。但是当把这个 url 放在我的 android 应用程序中时(带截击)不要获取任何东西。以前,当我在本地主机 (xampp) 中使用此 json 时,一切正常,但在释放主机时出现此问题
dbconfig.php
<?php
//Define your host here.
$servername = "xxx";
//Define your database username here.
$username = "xxx";
//Define your database password here.
$password = "*******";
//Define your database name here.
$dbname = "xxx";
?>
fetch_turbine2.php
<?php
include 'dbconfig.php';
$con = mysqli_connect($servername,$username,$password,$dbname);
//creating a query
$stmt = $con->prepare("SELECT POWER , ONE_THRUST_BEARING_METAL_TEMP
FROM turbine_table ORDER BY id DESC LIMIT 1;");
//executing the query
$stmt->execute();
//binding results to the query
$stmt->bind_result($t1,$t2);
$boiler = array();
//traversing through all the result
while($stmt->fetch()){
$temp = array();
$temp['t1'] = $t1;
$temp['t2'] = $t2;
array_push($boiler, $temp);
}
//displaying the result in json format
echo json_encode($boiler);
?>
java
StringRequest stringRequest1=new StringRequest(Request.Method.GET,"http://alibhm.epizy.com/fetch_turbine2.php",
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
try {
JSONArray array=new JSONArray(response);
for (int i=0; i < array.length(); i++) {
JSONObject product=array.getJSONObject(i);
String b1=product.getString("t1");
String b2=product.getString("t2");
final TextView a1=findViewById(R.id.pf1);
final TextView a2=findViewById(R.id.pf2);
a1.setText(b1);
a2.setText(b2);
}
} catch (JSONException e) {
e.printStackTrace();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
}
});
Volley.newRequestQueue(this).add(stringRequest1);
一周后我找到了答案:) 我的代码没有问题。一切都是由一些免费托管保护引起的。一些免费托管可以防止机器人。我的应用程序称为此主机的机器人。我换了我的主人,一切都很有魅力:)。我建议使用付费主机来传递问题。
我的免费主机中有这个 json
:http://alibhm.epizy.com/fetch_turbine2.php
如您所见,如果 运行 在浏览器中执行此操作并获取两个参数,则获取工作正常。但是当把这个 url 放在我的 android 应用程序中时(带截击)不要获取任何东西。以前,当我在本地主机 (xampp) 中使用此 json 时,一切正常,但在释放主机时出现此问题
dbconfig.php
<?php
//Define your host here.
$servername = "xxx";
//Define your database username here.
$username = "xxx";
//Define your database password here.
$password = "*******";
//Define your database name here.
$dbname = "xxx";
?>
fetch_turbine2.php
<?php
include 'dbconfig.php';
$con = mysqli_connect($servername,$username,$password,$dbname);
//creating a query
$stmt = $con->prepare("SELECT POWER , ONE_THRUST_BEARING_METAL_TEMP
FROM turbine_table ORDER BY id DESC LIMIT 1;");
//executing the query
$stmt->execute();
//binding results to the query
$stmt->bind_result($t1,$t2);
$boiler = array();
//traversing through all the result
while($stmt->fetch()){
$temp = array();
$temp['t1'] = $t1;
$temp['t2'] = $t2;
array_push($boiler, $temp);
}
//displaying the result in json format
echo json_encode($boiler);
?>
java
StringRequest stringRequest1=new StringRequest(Request.Method.GET,"http://alibhm.epizy.com/fetch_turbine2.php",
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
try {
JSONArray array=new JSONArray(response);
for (int i=0; i < array.length(); i++) {
JSONObject product=array.getJSONObject(i);
String b1=product.getString("t1");
String b2=product.getString("t2");
final TextView a1=findViewById(R.id.pf1);
final TextView a2=findViewById(R.id.pf2);
a1.setText(b1);
a2.setText(b2);
}
} catch (JSONException e) {
e.printStackTrace();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
}
});
Volley.newRequestQueue(this).add(stringRequest1);
一周后我找到了答案:) 我的代码没有问题。一切都是由一些免费托管保护引起的。一些免费托管可以防止机器人。我的应用程序称为此主机的机器人。我换了我的主人,一切都很有魅力:)。我建议使用付费主机来传递问题。