在汇编中接受用户输入？简单程序（在 macOS 上）

Question

我在使用这个接受用户名称并打印 "Hello, name here"

的简单程序时遇到了一些问题

到目前为止，这是我的代码...

%define SYSCALL_WRITE 0x2000004
%define SYSCALL_EXIT  0x2000001
%define SYSCALL_READ  0x2000003

SECTION .data
  prompt db "Enter name "
  text2 db "Hello, "

SECTION .bss
  name resb 16

SECTION .text
  global _start

_start:
  call _printText1
  call _getInput
  call _printText2
  call _printName
  mov rax, SYSCALL_EXIT
  mov rdi, 0
  syscall

_printText1:
  mov rax, SYSCALL_WRITE
  mov rdi, 1
  mov rsi, prompt
  mov rdx, 11
  syscall
  ret

_getInput:
  mov rax, SYSCALL_READ
  mov rdi, 0
  mov rsi, name
  mov rdx, 1
  syscall
  ret

_printText2:
  mov rax, SYSCALL_WRITE
  mov rdi, 1
  mov rsi, text2
  mov rdx, 7  
  syscall
  ret

_printName:
  mov rax, SYSCALL_WRITE
  mov rdi, 1
  mov rsi, name
  mov rdx, 16
  syscall
  ret

当我执行它时，输出不打印 "Hello, "。输入名称的第一个字母打印在下一个命令行之前...

nMy-MacBook:Assembly username$ ame

名称的其余部分被接受为命令参数，系统对此回复

-bash: ame: command not found

我到底做错了什么？我删除了 _getInput 和 _printName 函数，它仍然只打印 "Enter name " 而没有打印 "Hello, ".

谢谢。

Answer 1

在汇编中你必须考虑到每一点；尤其是在做输入输出的时候。

下面是您为 RDX 编辑的部分代码，其中我选择了一些任意长度。

最后一行显示命令行程序执行、提示、用户输入，然后是最终输出。

; reference:
; 

; lsb_release -a
; Distributor ID: Ubuntu
; Description:    Ubuntu 16.04.3 LTS
; Release:        16.04
; Codename:       xenial

; assemble and link
; nasm -f elf64 -g -F dwarf srsrso_001.s -o srsrso_001.o  && ld srsrso_001.o -o srsrso_001

;%define SYSCALL_WRITE 0x2000004
;%define SYSCALL_EXIT  0x2000001
;%define SYSCALL_READ  0x2000003

SECTION .data
  prompt db "Enter name "
  text2 db "Hello, ",0xa,0

        SYSCALL_WRITE equ       1
        SYSCALL_EXIT  equ       60
        SYSCALL_READ  equ       0

SECTION .bss
  name resb 0xff                ; some length

SECTION .text
  global _start

_start:
 call _printText1
 call _getInput
 call _printText2
 call _printName

  mov rax, 60
  mov rdi, 0
  syscall

_printText1:
  mov rax, SYSCALL_WRITE
  mov rdi, 1
  mov rsi, prompt
  mov rdx, 11
  syscall
  ret

_getInput:
  mov rax, SYSCALL_READ
  mov rdi, 0
  mov rsi, name
  mov rdx, 0xff ; some length
  syscall
  ret

_printText2:
  mov rax, SYSCALL_WRITE
  mov rdi, 1
  mov rsi, text2
  mov rdx, 7
  syscall
  ret

_printName:
  mov rax, SYSCALL_WRITE
  mov rdi, 1
  mov rsi, name
  mov rdx, 0xff ; some length
  syscall
  ret

示例输出：

$ ./srsrso_001
Enter name David John Lewis Benjamen Kyle Smith-Wenson
Hello, David John Lewis Benjamen Kyle Smith-Wenson

在汇编中接受用户输入？简单程序（在 macOS 上）

Accepting user input in assembly? Simple program (On macOS)

assembly

x86-64

mach-o

nasm